Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
101 comments Page 2 of 11.
Ritu Sehgal said:
1 decade ago
Let husband present age - x.
Let wife present age - y.
Let son present age - z.
The average age of husband, wife and son before 3 years was 27.
i.e Before 3 year (x-3)+(y-3)+(z-3)/3 = 27.
x-3+y-3+z-3 = 27*3.
x+y+z = 81+9.
x+y+z = 90.....(1).
The average age of wife and son before 5 years was 20.
i.e Before 5 years (y-5)+(z-5)/2 = 20.
y-5+z-5 = 20*2.
y+z = 40+10.
y+z = 50....(2).
Now by subtracting equation 2 from equation 1, we will find x = 40.
Let wife present age - y.
Let son present age - z.
The average age of husband, wife and son before 3 years was 27.
i.e Before 3 year (x-3)+(y-3)+(z-3)/3 = 27.
x-3+y-3+z-3 = 27*3.
x+y+z = 81+9.
x+y+z = 90.....(1).
The average age of wife and son before 5 years was 20.
i.e Before 5 years (y-5)+(z-5)/2 = 20.
y-5+z-5 = 20*2.
y+z = 40+10.
y+z = 50....(2).
Now by subtracting equation 2 from equation 1, we will find x = 40.
Sundar said:
1 decade ago
@Renu
The solution for your problem:
Lets take the age of father 10 yrs ago as x.
Then rest of the 5 members 10 yrs ago as y.
Now the mean age 10 yrs ago is = (x + y)/6 --(1)
and now as father is dead and all the ages of the other 5 members has risen by 10 each.
So mean age now =(y + 5(10))/6 ---(2)
Equating (1) and (2): (x+y)/6 = (y+50)/6
Be solving the above, we get x = 50.
So present age when he died
= x + 10
= 60 yrs.
The solution for your problem:
Lets take the age of father 10 yrs ago as x.
Then rest of the 5 members 10 yrs ago as y.
Now the mean age 10 yrs ago is = (x + y)/6 --(1)
and now as father is dead and all the ages of the other 5 members has risen by 10 each.
So mean age now =(y + 5(10))/6 ---(2)
Equating (1) and (2): (x+y)/6 = (y+50)/6
Be solving the above, we get x = 50.
So present age when he died
= x + 10
= 60 yrs.
Harpreet said:
1 decade ago
1. Av age of H+W+C=27.
Three years back their total age, we multiply 27 by 3 = 81 years.
Three years later age increased for three members = 3*3 = 9.
2. Current age of H+W+C = 90.
3. Av age of W+C = 20.
Five years back their total age, we multiply 20 by 2 = 40.
Five years later age increased for two members = 5*2 = 10.
4. Current age of W+C = 50.
5. Husband age = Current age of H+W+C-W+C = 90-50 = 40 years.
Three years back their total age, we multiply 27 by 3 = 81 years.
Three years later age increased for three members = 3*3 = 9.
2. Current age of H+W+C = 90.
3. Av age of W+C = 20.
Five years back their total age, we multiply 20 by 2 = 40.
Five years later age increased for two members = 5*2 = 10.
4. Current age of W+C = 50.
5. Husband age = Current age of H+W+C-W+C = 90-50 = 40 years.
(1)
Ravikumara. said:
6 years ago
a)=(x+y+z)/3 = 27------> (1) given
=(x+y+z) =3*27=81------> (2) 3years back
=(x+y+z) =81+(3*3) =90------> (3) present age.
B) =(x+y) /2= 20------> (4) given
= (x+y) =2*20=40------> (5) 5years back age
= (x+y) =40+(5*2)=50------> (6) present age of wife and child.
= x+y+z =90
= 50+z=90
=90-50 = 40 = z------> Present husband age (Or)
eq-3 subtracting with 6 => 90-50 = 40 husband's present age.
=(x+y+z) =3*27=81------> (2) 3years back
=(x+y+z) =81+(3*3) =90------> (3) present age.
B) =(x+y) /2= 20------> (4) given
= (x+y) =2*20=40------> (5) 5years back age
= (x+y) =40+(5*2)=50------> (6) present age of wife and child.
= x+y+z =90
= 50+z=90
=90-50 = 40 = z------> Present husband age (Or)
eq-3 subtracting with 6 => 90-50 = 40 husband's present age.
(1)
Murali said:
1 decade ago
Given that average age of husband, wife, child 3 years ago was 27 years
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
Vinod said:
1 decade ago
Ques- The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
, ...
Can anybody explain it easily. because i don't understand that why we took this condition - Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
, ...
Can anybody explain it easily. because i don't understand that why we took this condition - Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Ayesha said:
8 years ago
Seven years ago at the time of their marriage, the average age of a man and his wife was 28 years. At present, they have two children. Their daughter is 2 years older than their son. One year after the birth of the daughter, the average age of the man, wife and their daughter was 21 years, then the present age of the son is.
How do I solve this? Please help me.
How do I solve this? Please help me.
Ks Venkatesh said:
1 decade ago
Its simple:
Avg of 6 family members before 10 years is (Hus-10)+(wife-10)+(fath-10)+(othrs-30)/6 at 10 years ago.. By simpllifing abv we get (hus+wife+fath+othrs-60)/6
Present age average(Here babe replaces father): (Hus+wif+Babe+others)/6
As per given condition equate both the abv equ: U'll get Father's age=60 years..!! QUITE EASY NA ??
Avg of 6 family members before 10 years is (Hus-10)+(wife-10)+(fath-10)+(othrs-30)/6 at 10 years ago.. By simpllifing abv we get (hus+wife+fath+othrs-60)/6
Present age average(Here babe replaces father): (Hus+wif+Babe+others)/6
As per given condition equate both the abv equ: U'll get Father's age=60 years..!! QUITE EASY NA ??
Sayed Sirajunnisa said:
6 years ago
A family of six members bought a car 10 years ago, and had a road accident today, in which one of the family members died. The average age of the family at the time when they bought the car is same as of today. What was the age of the member who passed away?can anyone help me with this problem, I need solution to this Question.
(1)
Abu Kipa said:
1 year ago
Present age average of H+W+C,
(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)
Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).
Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)
Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).
Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(47)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers