Aptitude - Average - Discussion

A person has a wife and three children. The average age of his parents is 70 which is 40 to his age and his wife is 15 from the average age of her children. What is the average age of the whole family?

Can anyone solve this?

Thanks for providing the easiest solution @Loverboy.

3 years ago, their avg is 27.
((h-3) + (w-3) + (c-3) ) /3 = 27.

h+w+c = 90. (present).
5 years ago w & c is 20.

((w-5) + (c-5) ) /2 = 20.

w+c=50. (present).
(h+w+c) - (w+c) = 40.

h = 40 years.

Thanks @Ramya.

a)=(x+y+z)/3 = 27------> (1) given
=(x+y+z) =3*27=81------> (2) 3years back
=(x+y+z) =81+(3*3) =90------> (3) present age.

B) =(x+y) /2= 20------> (4) given
= (x+y) =2*20=40------> (5) 5years back age
= (x+y) =40+(5*2)=50------> (6) present age of wife and child.
= x+y+z =90
= 50+z=90
=90-50 = 40 = z------> Present husband age (Or)
eq-3 subtracting with 6 => 90-50 = 40 husband's present age.

A family of six members bought a car 10 years ago, and had a road accident today, in which one of the family members died. The average age of the family at the time when they bought the car is same as of today. What was the age of the member who passed away?can anyone help me with this problem, I need solution to this Question.

Your answer is correct. Thanks @Ramya.

Just find their present ages.

h + w + c /3 = 27.
h + w + c = 27 × 3 = 81.
(But this total sum was 3 years ago, to find today's total sum, add 3 years of husband, wife and child in 81, 3 + 3 + 3 =9).

h + w + c =81 + 9 = 90 -----> A.

In the same way,
w + c /2 = 20
w+c = 40 ( but it was 5 years ago, so add 5 to both wife and child total of 10).

w + c = 40 + 10 =50 ------> B
We got our A and B equations; if we combine them, we will find our answer.

h + 50= 90 ( we have put equation B in A),
h = 90 - 50,
h = 40,
So, the husband's age is 40.

Question: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died?

Can anyone help me to find solution for this question AS SOON AS POSSIBLE?

@Renu

The solution for your problem:

Lets take the age of father 10 yrs ago as x.
Then rest of the 5 members 10 yrs ago as y.

Now the mean age 10 yrs ago is = (x + y)/6 --(1)

and now as father is dead and all the ages of the other 5 members has risen by 10 each.

So mean age now =(y + 5(10))/6 ---(2)

Equating (1) and (2): (x+y)/6 = (y+50)/6

Be solving the above, we get x = 50.

So present age when he died

= x + 10

= 60 yrs.

Ques- The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
, ...

Can anybody explain it easily. because i don't understand that why we took this condition - Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.