Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 15)
15.
A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half (1/2). The number of pupils in the class is:
10
20
40
73
Answer: Option
Explanation:

Let there be x pupils in the class.

Total increase in marks = x x 1 = x
2 2

x = (83 - 63)    x = 20      x= 40.
2 2

Discussion:
123 comments Page 8 of 13.

Ravi said:   1 decade ago
Let total of other students be x and number of students be n,

(x+83)/n - (x+63)/n = 1/2.

(x+83-x-63)/n = 1/2.

20/n = 1/2.

Therefore n = 40.

Mohit Tomar said:   9 years ago
Let as take, m is actual total marks of students and p is number of the pupil.

Difference between average = 1/2.
m/p - (m+20)/p = 1/2.
p = 40.

Ajay said:   1 decade ago
Ans of Savinder question
Let total no of cand-x
Dec in aver- 50-45=5
Total dec in numbers= 5x

then, 5x= 100(90-60)
x=600 ( Ans)
(1)

Tukaram D. Yedale said:   1 decade ago
Hi guys !

Let no.of people = x (83/x) - (63/x) = 1/2 after solving this we get x= 40 it is very easy method to understand is't it ?

Utsav Sinha said:   8 years ago
Simple logic.

Let no.of candidate = x.
Their average marks =y.
Generate an equation,
xy+83-63=x(y+1/2).
Solving we get y=40.

Shubham said:   3 years ago
Here, the Question says A Pupil's which refers to only one student.

While pupils stand for multiple students.


Am I right?
(7)

Abhishek said:   8 years ago
@Utsav Sinha.

RHS should be;
X (y + 1/2y). Because average is increasing by half that means avg + 1/2 of avg.

Karthy said:   1 decade ago
The average increase for one person is 0.5

Total increase is 20

Therefore Total no of pupil =20/0.5 = 40.
(2)

Chinmay said:   8 years ago
Total marks=x,
Number of pupils=y,
Average=x/y.
But,
(x+y)/20=x/y+1/2,
(x+20)/y=(2x+y)/2y,
Therefore y=40.

Deepak kumar said:   8 years ago
Let x is average marks when total marks are 63.
Replacement,

83 - 63 = 20.
Then, x + 20 = x\2.
X = 40.


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