Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 15)
15.
A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half (1/2). The number of pupils in the class is:
Answer: Option
Explanation:
Let there be x pupils in the class.
| Total increase in marks = |  |
x x | 1 |  |
= | x |
| 2 | 2 |
 |
x | = (83 - 63)  |
x | = 20 x= 40. |
| 2 | 2 |
Discussion:
123 comments Page 9 of 13.
Dinesh said:
1 decade ago
Its very simple given difference of avg is half hence,
(83/x)-(63/x) = 0.5.
Hence by solve x = 40.
(83/x)-(63/x) = 0.5.
Hence by solve x = 40.
Pawan yadav said:
7 years ago
Let x = total number of student.
Increase 1/2 means x * 1/2 = x/2,
Means x/2 = 83-63
x = 40.
Increase 1/2 means x * 1/2 = x/2,
Means x/2 = 83-63
x = 40.
Rav said:
1 decade ago
In the question above
is "A pupil's" mean "A student" ?
is "A pupil's" mean "A student" ?
Abhishek Ojha said:
8 years ago
@Shubham.
In your case, You calculated Average Marks Not num of the pupil.
In your case, You calculated Average Marks Not num of the pupil.
Mr.Pirate said:
3 years ago
No of pupil = x.
Avg = Total/no. Of pupil.
1/2=(83-63)/x.
0.5=20/x,
X=40.
Avg = Total/no. Of pupil.
1/2=(83-63)/x.
0.5=20/x,
X=40.
(45)
Mudit said:
7 years ago
I didn't understand why we are multiplying x with 1/2? Please tell me.
Krishna kanth said:
1 decade ago
I didn't understand anything please please please some body explain.
MGM said:
8 years ago
How about this?
(83- 63)/ ? = 1/2
that is 20/ (1/2) = ?
Ans 40.
(83- 63)/ ? = 1/2
that is 20/ (1/2) = ?
Ans 40.
Nehanshu raj badholiya said:
1 decade ago
Rakesh's and habi bbhaijan both are correct so don't get confused.
Danny Blac said:
1 decade ago
@Midhun J.
You are right. I can so much relate with your answer.
You are right. I can so much relate with your answer.
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