Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Answer: Option
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
 Required number of tiles = |
 |
1517 x 902 |  |
= 814. |
| 41 x 41 |
Discussion:
56 comments Page 3 of 6.
Anc said:
8 years ago
Where does the 1517comes from?
Arpan jadhao said:
8 years ago
How 1517 comes from?
I didn't understand it. Please explain me.
I didn't understand it. Please explain me.
ABDULLAH AKHTAR said:
9 years ago
@Narayanan.
Thanks for explaining it.
Thanks for explaining it.
Rohit said:
8 years ago
HCF is taken because we want the least no.of tiles in this question. If we want least no of tiles then we have to maximise the dimensions of tiles.
So HCF (Higher Common Factor) is used to maximise the dimensions of tiles.
So HCF (Higher Common Factor) is used to maximise the dimensions of tiles.
Tina said:
8 years ago
I am not getting the solution properly. Please, could anyone explain me?
Roop said:
8 years ago
Hcf is calculated because for least tiles we need area of the square be maximum.
Bhavishya said:
8 years ago
Thank you so much for the explanation.
Sakshi said:
8 years ago
Thank you @Srivalli.
Sudarshan jain said:
6 years ago
Thanks all.
Koushik kallamadi said:
1 decade ago
Hi friends,
We can also use the dimensions (9.02*9.02) + (6.15*6.15) +2(2.87*2.87) +7(0.41*0.41) and totally 11 square tiles of different lengths.
We can also use the dimensions (9.02*9.02) + (6.15*6.15) +2(2.87*2.87) +7(0.41*0.41) and totally 11 square tiles of different lengths.
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