Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
814
820
840
844
Answer: Option
Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) cm2.

Required number of tiles = 1517 x 902 = 814.
41 x 41

Discussion:
57 comments Page 2 of 6.

ABDULLAH AKHTAR said:   1 decade ago
@Narayanan.

Thanks for explaining it.

Sakshi said:   8 years ago
Thank you @Srivalli.

Anoop said:   10 years ago
@Suresh.

Thank you for explaining why HCF is used here..

Pink_love said:   10 years ago
@Jhanvi.

In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).

And for HCF.

1517 = 37 * 41,
902 = 22 * 41,

So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.

Ramesh said:   10 years ago
I didn't understand the Last step multiplication. Someone help me.

Abhi said:   10 years ago
Please tell me how many tiles will be used in that room whose length or breath is 20 m and 16 cm or 15 m 60 cm.

Sathyaraj k said:   10 years ago
Thank you @Ibrahimsha.

Shridhar said:   10 years ago
Thank you for your solution @Ibrahimsha.

Vinay said:   9 years ago
Why squares need to be of same size?

S. Nipin said:   9 years ago
Suppose if the question was asked to find maximum no. of tiles then how to find the answer?


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