Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
814
820
840
844
Answer: Option
Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) cm2.

Required number of tiles = 1517 x 902 = 814.
41 x 41

Discussion:
56 comments Page 2 of 6.

S. Nipin said:   9 years ago
Suppose if the question was asked to find maximum no. of tiles then how to find the answer?

Vinay said:   9 years ago
Why squares need to be of same size?

Shridhar said:   9 years ago
Thank you for your solution @Ibrahimsha.

Sathyaraj k said:   9 years ago
Thank you @Ibrahimsha.

Abhi said:   9 years ago
Please tell me how many tiles will be used in that room whose length or breath is 20 m and 16 cm or 15 m 60 cm.

Ramesh said:   9 years ago
I didn't understand the Last step multiplication. Someone help me.

Pink_love said:   9 years ago
@Jhanvi.

In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).

And for HCF.

1517 = 37 * 41,
902 = 22 * 41,

So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.

Anoop said:   9 years ago
@Suresh.

Thank you for explaining why HCF is used here..

Naqi Zaidi said:   8 years ago
HCF of any two or more numbers tells the highest possible no that can divide all the numbers. Since the question asks the minimum no of tiles, so it means you need a maximum possible size of the tile. Which will ensure minimum no of tiles?

If the question says that maximum tiles then you will calculate LCM.

Soniya said:   8 years ago
Why hcf is taken? Please explain.


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