Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Answer: Option
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
Required number of tiles = |
![]() |
1517 x 902 | ![]() |
= 814. |
| 41 x 41 |
Discussion:
57 comments Page 2 of 6.
ABDULLAH AKHTAR said:
1 decade ago
@Narayanan.
Thanks for explaining it.
Thanks for explaining it.
Sakshi said:
8 years ago
Thank you @Srivalli.
Anoop said:
10 years ago
@Suresh.
Thank you for explaining why HCF is used here..
Thank you for explaining why HCF is used here..
Pink_love said:
10 years ago
@Jhanvi.
In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).
And for HCF.
1517 = 37 * 41,
902 = 22 * 41,
So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.
In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).
And for HCF.
1517 = 37 * 41,
902 = 22 * 41,
So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.
Ramesh said:
10 years ago
I didn't understand the Last step multiplication. Someone help me.
Abhi said:
10 years ago
Please tell me how many tiles will be used in that room whose length or breath is 20 m and 16 cm or 15 m 60 cm.
Sathyaraj k said:
10 years ago
Thank you @Ibrahimsha.
Shridhar said:
10 years ago
Thank you for your solution @Ibrahimsha.
Vinay said:
9 years ago
Why squares need to be of same size?
S. Nipin said:
9 years ago
Suppose if the question was asked to find maximum no. of tiles then how to find the answer?
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