Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Answer: Option
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
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1517 x 902 | ![]() |
= 814. |
41 x 41 |
Discussion:
56 comments Page 1 of 6.
Richy said:
7 years ago
@All.
If we want to get the least number of tiles, the largest tiles must be used. This is why hcf is used. If you want to get the most number of tiles, then, the smallest tiles will be used, which is lcm.
If we want to get the least number of tiles, the largest tiles must be used. This is why hcf is used. If you want to get the most number of tiles, then, the smallest tiles will be used, which is lcm.
(8)
Srivalli said:
8 years ago
1m=100 Cms, so convert 15meters *100=1500+17cms=1571,
Like wise 9meters*100=900+2cms=902cms.
Like wise 9meters*100=900+2cms=902cms.
(4)
Siddharth said:
8 years ago
@Tina.
The dimensions of the room is 1517cm X 902cm.
Square tiles of the same side are only to be used. So dimensions of the square tiles should not be in integral metres. Since no. of square tiles to be paved are whole numbers, 1517 and 902 should be divisible by a number which gives the number of square tiles to be paved along length and breadth.
Thus hcf is used.
Area of room / Area of 1 tile = No. of tiles.
= ( 1517 X 902 ) / ( 41 X 41 ) = 37 X 22 = 814 tiles.
The dimensions of the room is 1517cm X 902cm.
Square tiles of the same side are only to be used. So dimensions of the square tiles should not be in integral metres. Since no. of square tiles to be paved are whole numbers, 1517 and 902 should be divisible by a number which gives the number of square tiles to be paved along length and breadth.
Thus hcf is used.
Area of room / Area of 1 tile = No. of tiles.
= ( 1517 X 902 ) / ( 41 X 41 ) = 37 X 22 = 814 tiles.
(4)
Ibrahimsha said:
1 decade ago
902)1517(1
902
------
615)902(1
615
---
287)615(2
574
---
41)287(7
287
---
0
By this method of successful division, remainder goes 0. Last divisor forms your req. HCF....
So 41 is ur HCF :-)
902
------
615)902(1
615
---
287)615(2
574
---
41)287(7
287
---
0
By this method of successful division, remainder goes 0. Last divisor forms your req. HCF....
So 41 is ur HCF :-)
(3)
Harish said:
7 years ago
Here 41 * 37=1517 and 41 * 22=902.
So, 41 comes in both the no. (which is called hcf).
Now the area of the floor is 1512 * 902.
So least no. of tiles to cover the floor = n * 41^2 (as square tile can be taken of length 41).
Therefore n =37*22 =814.
So, 41 comes in both the no. (which is called hcf).
Now the area of the floor is 1512 * 902.
So least no. of tiles to cover the floor = n * 41^2 (as square tile can be taken of length 41).
Therefore n =37*22 =814.
(2)
Jhanvi said:
9 years ago
How you got 1517 and 902? Please explain.
(1)
Raghuvansh said:
6 years ago
Thanks for your explanation of HCF @Ibrahimsha.
(1)
Shekarreddy said:
7 years ago
Why we use HCF here?
(1)
Anuj Chhetri said:
8 years ago
We need that size of square which must occupy the entire space. If we take side of some other square, then 100% some space gona left as we can't bread the last tile. If we take the hcf, then we can get the side of square which is divisible by length and breadth both exactly.
Richa said:
8 years ago
Thanks @Ibrahimsha.
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