Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Answer: Option
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
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1517 x 902 | ![]() |
= 814. |
41 x 41 |
Discussion:
56 comments Page 1 of 6.
Siddharth said:
8 years ago
@Tina.
The dimensions of the room is 1517cm X 902cm.
Square tiles of the same side are only to be used. So dimensions of the square tiles should not be in integral metres. Since no. of square tiles to be paved are whole numbers, 1517 and 902 should be divisible by a number which gives the number of square tiles to be paved along length and breadth.
Thus hcf is used.
Area of room / Area of 1 tile = No. of tiles.
= ( 1517 X 902 ) / ( 41 X 41 ) = 37 X 22 = 814 tiles.
The dimensions of the room is 1517cm X 902cm.
Square tiles of the same side are only to be used. So dimensions of the square tiles should not be in integral metres. Since no. of square tiles to be paved are whole numbers, 1517 and 902 should be divisible by a number which gives the number of square tiles to be paved along length and breadth.
Thus hcf is used.
Area of room / Area of 1 tile = No. of tiles.
= ( 1517 X 902 ) / ( 41 X 41 ) = 37 X 22 = 814 tiles.
(4)
Shanthi said:
1 decade ago
Length and breath are given.
So area of rectangle is lxb.
Also they are askin to find the least no. of square tiles.
For square tiles we need the area.
In a square al the sides are equal.
Hcf is the highest common factor of 1517 and 902.
So 41 is the hcf n area of square is 41^2.
So divide area of rect by area of square.
So area of rectangle is lxb.
Also they are askin to find the least no. of square tiles.
For square tiles we need the area.
In a square al the sides are equal.
Hcf is the highest common factor of 1517 and 902.
So 41 is the hcf n area of square is 41^2.
So divide area of rect by area of square.
Ibrahimsha said:
1 decade ago
902)1517(1
902
------
615)902(1
615
---
287)615(2
574
---
41)287(7
287
---
0
By this method of successful division, remainder goes 0. Last divisor forms your req. HCF....
So 41 is ur HCF :-)
902
------
615)902(1
615
---
287)615(2
574
---
41)287(7
287
---
0
By this method of successful division, remainder goes 0. Last divisor forms your req. HCF....
So 41 is ur HCF :-)
(3)
Naqi Zaidi said:
8 years ago
HCF of any two or more numbers tells the highest possible no that can divide all the numbers. Since the question asks the minimum no of tiles, so it means you need a maximum possible size of the tile. Which will ensure minimum no of tiles?
If the question says that maximum tiles then you will calculate LCM.
If the question says that maximum tiles then you will calculate LCM.
Shashank said:
1 decade ago
Since hcf is a prime no. , how we can find the hcf of such big numbers.
For those who want to know why hcf::.
As we have to set square tiles in a rect. Floor that's why we need a comman factor for both length and breadth so that the no. Of tiles is a natural number but not a fraction!
For those who want to know why hcf::.
As we have to set square tiles in a rect. Floor that's why we need a comman factor for both length and breadth so that the no. Of tiles is a natural number but not a fraction!
Anuj Chhetri said:
8 years ago
We need that size of square which must occupy the entire space. If we take side of some other square, then 100% some space gona left as we can't bread the last tile. If we take the hcf, then we can get the side of square which is divisible by length and breadth both exactly.
Narayanan said:
9 years ago
The least number is asked that means a single tile with the maximum dimension.
For this try LCM , you will get the maximum number of tiles with minimum dimensions whereas, in HCF, you will get the largest dimension possible. So that only HCF is used to find the answer.
For this try LCM , you will get the maximum number of tiles with minimum dimensions whereas, in HCF, you will get the largest dimension possible. So that only HCF is used to find the answer.
Pink_love said:
9 years ago
@Jhanvi.
In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).
And for HCF.
1517 = 37 * 41,
902 = 22 * 41,
So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.
In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).
And for HCF.
1517 = 37 * 41,
902 = 22 * 41,
So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.
Harish said:
7 years ago
Here 41 * 37=1517 and 41 * 22=902.
So, 41 comes in both the no. (which is called hcf).
Now the area of the floor is 1512 * 902.
So least no. of tiles to cover the floor = n * 41^2 (as square tile can be taken of length 41).
Therefore n =37*22 =814.
So, 41 comes in both the no. (which is called hcf).
Now the area of the floor is 1512 * 902.
So least no. of tiles to cover the floor = n * 41^2 (as square tile can be taken of length 41).
Therefore n =37*22 =814.
(2)
Rohit said:
8 years ago
HCF is taken because we want the least no.of tiles in this question. If we want least no of tiles then we have to maximise the dimensions of tiles.
So HCF (Higher Common Factor) is used to maximise the dimensions of tiles.
So HCF (Higher Common Factor) is used to maximise the dimensions of tiles.
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