Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 3 of 8.
Salman said:
8 years ago
Thanks to all for giving the explanation.
VAN said:
8 years ago
So, x is squared because it is assumed that the two x's are of equal value?
Vijeta said:
8 years ago
Nice explanation. Thank you all.
GAYATRI said:
9 years ago
@All.
Please draw the picture first.
Two roads intersecting each other like " + " sign not like "x" sign. One road has an area of 60x other one has 40x. There is a common area of x^2.
Please draw the picture first.
Two roads intersecting each other like " + " sign not like "x" sign. One road has an area of 60x other one has 40x. There is a common area of x^2.
(1)
Noble Phelix said:
9 years ago
Good job @Ayoosh.
Pratiti Das said:
9 years ago
How come two concentric roads have 60x + 40x?
Aayushi said:
9 years ago
Where is 291?
How to solve this?
How to solve this?
T BALAJI said:
9 years ago
Thank you @Ayoosh.
Savita said:
9 years ago
Thanks @Priyanka for the answer.
Ammu said:
9 years ago
Thanks for the explanation.
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