Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
2.91 m
3 m
5.82 m
None of these
Answer: Option
Explanation:

Area of the park = (60 x 40) m2 = 2400 m2.

Area of the lawn = 2109 m2.

Area of the crossroads = (2400 - 2109) m2 = 291 m2.

Let the width of the road be x metres. Then,

60x + 40x - x2 = 291

x2 - 100x + 291 = 0

(x - 97)(x - 3) = 0

x = 3.

Video Explanation: https://youtu.be/R3CtrAKGxkc

Discussion:
76 comments Page 4 of 8.

Ammu said:   10 years ago
Thanks for the explanation.

Lavanya said:   10 years ago
@Ayoosh,

60 and 40 are not the lengths of the roads. 60 is the length and 40 is the width. Still, have a confusion. Could anyone please explain it clearly?

Lalitha said:   10 years ago
Thank you @Ayoosh.

Imtiyaj said:   10 years ago
God job @Ayoosh.

Arjun said:   10 years ago
(60x + 40x -x^2 this is the area of cross roads alone. 60 and 4O are lengths of cross roads and x is the breadth.

X^2 is subtracted because the meeting of crossroads, the calculated area overlaps. So - X^2.

ARAVIND said:   10 years ago
Great explanation @Ayoosh.

Priyanka said:   1 decade ago
We can also subtract the width of the road from length and breadth of the road and multiply the values to get the area of the lawn i.e.

Let the width be x.

Length of lawn = 60 - x.

Breadth of lawn = 48 - x.

(60 - x) (40 - x) = 2109. As given in question.

X^2 - 100x - 291 = 0.

X = 3 and 97.

The value 3 is there in the given option. So, width of the road is 3m.
(1)

Saila said:   1 decade ago
@Puskar,

You may go through Diego's answer for better understanding.

Puskar prasun said:   1 decade ago
Guys! it should be 2x^2 instead of simply x^2? don't you all agree?

Peter said:   1 decade ago
@Rkbm your answer best answer.


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