Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 8 of 8.
Tanya said:
1 decade ago
Its because the area of 2 roads has come out to be 291m2. Rest of the explaination has been given by prajwal.
Shreya said:
1 decade ago
My doubt is
60x+40x-x2=291?.
60x+40x-x2=291?.
Prajwal said:
1 decade ago
I got it. Its because. 60 and 40 get multiplies to width and. Since there are two cross roads. There will be a common space for two roads. (width of two cross roads is width^2).
Lekshmi said:
1 decade ago
Same doubt as sai said above,
60x + 40x - x2 = 291?
60x+40x?
60x + 40x - x2 = 291?
60x+40x?
Sai said:
1 decade ago
What is the need of 60x + 40X -pow (x, 2) ?
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