Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
2.91 m
3 m
5.82 m
None of these
Answer: Option
Explanation:

Area of the park = (60 x 40) m2 = 2400 m2.

Area of the lawn = 2109 m2.

Area of the crossroads = (2400 - 2109) m2 = 291 m2.

Let the width of the road be x metres. Then,

60x + 40x - x2 = 291

x2 - 100x + 291 = 0

(x - 97)(x - 3) = 0

x = 3.

Video Explanation: https://youtu.be/R3CtrAKGxkc

Discussion:
75 comments Page 7 of 8.

Amrut said:   2 decades ago
thnks ayoosh & nakul

Golu said:   2 decades ago
Why 97 was not taken as answer?

Manish said:   2 decades ago
Thanks ayoosh.

Nayan said:   2 decades ago
Thnks nakul.

Nakul gowda said:   2 decades ago
60x + 40x includes the intersection part twice..so to include the intersection part only once, subtract area of intersection part once, ie, x^2....got it yet..

Sujay ramesh said:   2 decades ago
Thanks ayoosh. Your explanation is good :).

Ayoosh said:   2 decades ago
If we dont subtract the X^2 THEN the area of intercrossing will be doubled since its accountd in area of both roads !! thats why we subtract x^2
(2)

Jhola said:   2 decades ago
Very good ayoosh.

Ayoosh said:   2 decades ago
For all having probs in the 60x + 40x - x^2!!!!

See road is a rect. and they are intercrossing. let the width be x, then for one road area will be 40x and for the other road will be 60x since 60 and 40 will be the lengths of road.

now, we area of roads is 291 m2, so

ar(road1) + ar(road2) - ar(intercrossing)
60x + 40x - x^2 = 291 and then on you can find the ans
(9)

Naju said:   2 decades ago
Draw the figure you can c two cross road intersect, so we need to subtract it.


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