Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 2 of 8.
Himanshu said:
7 years ago
Why only square of width is taken and not length?
(1)
Vijay said:
7 years ago
@Ankanna.
Your explanation really helped me. Thanks.
Your explanation really helped me. Thanks.
Shivangi goel said:
7 years ago
How this quadratic equation is formed in x?
Pooja said:
7 years ago
Thank you @Ayoosh.
Theodore said:
8 years ago
What will be the LENGTH of the road? Can Anyone help me to find out the answer?
Smita said:
8 years ago
Thanks @Ayoosh.
Torikul said:
8 years ago
Thanks for your good explanation @Priyanka.
Bond said:
8 years ago
Thanks @Ayoosh.
Bhargavi said:
8 years ago
When two roads intersecting like a +.
So road 1 area is l*b =60*x rectangle road 2 area is l*b =40*x rectangle intersecting place is in a square shape so side =x.; the area is x^2.
In road 1 and road2 we are calculating intersecting point area two times so we have to Subtract that square shape intersecting point.
So road 1 area is l*b =60*x rectangle road 2 area is l*b =40*x rectangle intersecting place is in a square shape so side =x.; the area is x^2.
In road 1 and road2 we are calculating intersecting point area two times so we have to Subtract that square shape intersecting point.
(3)
Tamil said:
8 years ago
Well said @Ayoosh.
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