Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 11)
11.
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
1520 m2
2420 m2
2480 m2
2520 m2
Answer: Option
Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) m2 = 2520 m2.

Discussion:
20 comments Page 2 of 2.

Himanshu said:   1 decade ago
(l+b) = 103 ...........(i).
(l-b) = 23 ...........(ii).

Subtracting eq.(ii) from (i).

(l+b)-(l-b) = 103-23.
2b = 80.
b = 40.
(1)

Silambarasan said:   1 decade ago
How is possible l 63 and b 40?

Ruby said:   7 years ago
l-b=23
then put l-23=b in it 2(i+b)=206
Solve it l=63 then substitut valu of l,
63-23=b , b=40 lb=63*40=2520.

Parashuram Rathod said:   9 years ago
2 (l + b) = 206.

Why multiply by 2?

Ravneet said:   9 years ago
63 - 40 = 23.
i.e. l - b = 23.
And 63 * 40 = 2520.

Susan said:   9 years ago
How l+b =103?

Mishi said:   1 decade ago
Let the length is x and breadth is y. Then 2x+2y = 206. So we know x-y = 23.

Then we x+y+x-y = 126. So we got x = 63. Then y = 40. After multiple 63*40 = 2520 cm.

Srini said:   1 decade ago
Any one explain clearly friends?

Jaimin said:   1 decade ago
(L-b) = 23.
Perimeter of rectangle L+B+L+B=206.

Now,
L=23+b.

Put this value in perimeter formula,
Get value of L.

You can easily find the value of b by [(L-B)=23].
Product of L and B is your answer.

Meghna said:   1 decade ago
l+b=103
l-b=23
-------
2b=80
-------
So b=40, substitute b in any equation you get l= 63
Area =lb= 63*40= 2520m^2


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