Aptitude - Alligation or Mixture - Discussion

Thanks victor. Your way of explanation is short and simple.

Excellant victor.

As kiran said about getting the percentage. How its possible, can you explain it clealy of getting 60%, 40 %.

Victor your way of doing this problem is less time consumable. Thank you.

Can you solve this problem with allegation formula ?

Here is simple approach

3/5-1/2=1:1

Simple solution for this;

Given: Vessel contains...water -- 3 parts. Syrup -- 5 parts.

Required: Both should be half-- half

Sol: take one part of syrup and add it to water i.e then both will have 4 parts.

So divide syrup into 5 parts.then one part is 1/5, that is the solution.

Uttam, surender and ameer has cleared out my confusion regarding this problem. Thanks a lot.

Thanks ameer for your detailed explanation...

Thank you Surender and Utham...i hav tried to explain the answer in detail

Let the volume of vessel be x
quantity of water = 3/8 x
quantity of syrup = 5/8 x

Let the amount of mixture removed be y
The removed mixture contains 3/8 y of water and 5/8 y of syrup

So quantity of water left in the mixture=3/8[x-y]
quantity of syrup left in the mixture 5/8 [x-y]

According to the question,the amount of mixture removed is replaced later by water,so that the syrup an water would be exactly half each of the mixture...

so when more water is added to the existing water in the mixture..

3/8[x-y] + y = 5/8[x-y]
3x/8 - 3y/8 +y = 5x/8 - 5y/8
y = 2x/8 - 2y/8
8y=2[x-y]
4y=x-y
x=5y
y=1/5 x