Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
8 |
Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
8 |
![]() |
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
8 | 8 |
5x + 24 = 40 - 5x
10x = 16
![]() |
8 | . |
5 |
So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
5 | 8 | 5 |
Discussion:
198 comments Page 1 of 20.
Sandhya said:
2 decades ago
Can you give a shortcut for this?
Kiran said:
2 decades ago
As there are 3 parts of water and 5 parts of syrup.
total upto 8 parts.In terms of percentage,syrup is 60% and water is 40%.So syrup content to be reduced to 10% and water content to be increased to 10%,total constitutes to 10%+10%=20%.
finally 20%=20/100=1/5
total upto 8 parts.In terms of percentage,syrup is 60% and water is 40%.So syrup content to be reduced to 10% and water content to be increased to 10%,total constitutes to 10%+10%=20%.
finally 20%=20/100=1/5
(1)
Murali said:
1 decade ago
I did not get last Step. Could you please explain how it was?
So, part of the mixture replaced =
(8/5) * (1/8) =1/5.
So, part of the mixture replaced =
(8/5) * (1/8) =1/5.
SurendraReddy said:
1 decade ago
NOTE: Liquid = Mixed substance (water,syrup)
Let the volume of the vessel = x liters.
Out of this x liters 3/8(x) is water & 5/8(x) is syrup.
Let y liters of liquid is taken out. So out of this y liters 3/8(y) is water and 5/8(y) is syrup.
The water in the remaining liquid is 3/8(x-y) .
The syrup in the remaining liquid is 5/8(x-y).
Now y liters of water is added to the remaining liquid so that the final liquid contains half water and half syrup.
=> 3/8(x-y)+y=5/8(x-y)
=>y=1/5(x)
or y = 1/5(x).
Answer: The amount of liquid drawn out = The amount of water added = 1/5 of x.
Let the volume of the vessel = x liters.
Out of this x liters 3/8(x) is water & 5/8(x) is syrup.
Let y liters of liquid is taken out. So out of this y liters 3/8(y) is water and 5/8(y) is syrup.
The water in the remaining liquid is 3/8(x-y) .
The syrup in the remaining liquid is 5/8(x-y).
Now y liters of water is added to the remaining liquid so that the final liquid contains half water and half syrup.
=> 3/8(x-y)+y=5/8(x-y)
=>y=1/5(x)
or y = 1/5(x).
Answer: The amount of liquid drawn out = The amount of water added = 1/5 of x.
(4)
Madhu said:
1 decade ago
Excellent Kiran! Your answer is very nice.
Vigneshwaran K said:
1 decade ago
Hai I can't understand the steps can you please give me the understandable steps.
Thank you.
Thank you.
Nitesh said:
1 decade ago
@ Surendrareddy.
You are rocking. This is the right way.
You are rocking. This is the right way.
Uma said:
1 decade ago
I am agree with Siri. Your way of explanation is also excellent. Thanks.
Amuthan said:
1 decade ago
Great work Surendara Reddy.
Bindhureddy said:
1 decade ago
@surendrareddy. Your way of explanation is good. Moreover it is easy to do.
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