Aptitude - Alligation or Mixture - Discussion

@Surender reddy. its nice approach to solve it thanks..

Your great surender. Thanks a lot. Really that is very good explanation.

Instead of remembering the formulas you came with the theory.

And concept. Good excellent. Thank you for your post.

How we will get 60% of syrup from 5 parts of syrup and 40% of water from 3 parts of water which is explained in Kiran's answer?.

Please explain in detail. Please.

Yes mahi, something wrong with Kiran's answer.

3/8= 37.5%
5/8= 62.5%
And its not 40% and 60% as told by kiran

@Mahi and Kiran

Since it is 3 parts and 5 parts...totally 8.

50% of 8 is 4 and 40% of 8 is 3.

So 60% of 8 is 5 parts.

Hope you understand.

Let X=volume of vessel

Y=volume of mix taken out.

Initially,

volume of water in vessel=3X/8
volume of syrup in vessel=5X/8
Y=volume of mix taken out=volume of water added.

Now,
drawn off mix may contain,
volume of water=3Y/8.
volume of syrup=5Y/8.

after mix drawn off,
volume of water in the vessel=(3X/8)-(3Y/8)=(3/8)(X-Y).
volume of syrup in the vessel=(5X/8)-(5Y/8)=(5/8)(X-Y).

After water added, volume of water in the vessel
=[(3X/8)-(3Y/8)]+Y
=[(3/8)(X-Y)]+Y.


hence from the Question,in the vessel, volume of water

=volume of syrup

[(3/8)(X-Y)]+Y=(5/8)(X-Y)

10Y=2X

Y=(1/5)*X

So volume of water should be added is (1/5)th of volume of vessel.

Thanks it is really a good way to solve it.

Uttam and surender. Your answer is perfect. Kiran is wrong.

Thank you Surender and Utham...i hav tried to explain the answer in detail

Let the volume of vessel be x
quantity of water = 3/8 x
quantity of syrup = 5/8 x

Let the amount of mixture removed be y
The removed mixture contains 3/8 y of water and 5/8 y of syrup

So quantity of water left in the mixture=3/8[x-y]
quantity of syrup left in the mixture 5/8 [x-y]

According to the question,the amount of mixture removed is replaced later by water,so that the syrup an water would be exactly half each of the mixture...

so when more water is added to the existing water in the mixture..

3/8[x-y] + y = 5/8[x-y]
3x/8 - 3y/8 +y = 5x/8 - 5y/8
y = 2x/8 - 2y/8
8y=2[x-y]
4y=x-y
x=5y
y=1/5 x

Thanks ameer for your detailed explanation...