Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
| Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
| 8 |
| Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
| 8 |
|
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
| 8 | 8 |
5x + 24 = 40 - 5x
10x = 16
x = |
8 | . |
| 5 |
| So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
| 5 | 8 | 5 |
Discussion:
201 comments Page 1 of 21.
Ankush said:
3 weeks ago
3Lwater + 5L syrup = 8L mix.
Now 1 unit of mix will also have 3 parts water and 5 parts syrup,
Let 1 unit be 800 ml for easy calculation.
And in 800ml we have 300ml water + 500ml syrup
Now, remove 1 unit from the total, you will have a mix of 7.2L.
removed 1unit = 800ml in 7.2L × 5/8 = 4.5 L syrup left.
And add 800ml of water in its place.
New ratio of mix 4.5l syrup: 2.7 old +0.8 newly added
4.5:3.5 we need 4:4 for both equal
Remove 1 more unit from the mix.
7.2 - 0.8 = 6.4L.
Syrup left 6.4L × 5/8 = 4.0L
Add water in place of 800ml
Now you have 4L syrup: 4L water.
Replacement of syrup with water = 800ml × 2 = 1.6L.
Now, how much replacement from the original 8L in ratio?
So, 1.6/8 total replacement reduces to 1/5(ans).
Now 1 unit of mix will also have 3 parts water and 5 parts syrup,
Let 1 unit be 800 ml for easy calculation.
And in 800ml we have 300ml water + 500ml syrup
Now, remove 1 unit from the total, you will have a mix of 7.2L.
removed 1unit = 800ml in 7.2L × 5/8 = 4.5 L syrup left.
And add 800ml of water in its place.
New ratio of mix 4.5l syrup: 2.7 old +0.8 newly added
4.5:3.5 we need 4:4 for both equal
Remove 1 more unit from the mix.
7.2 - 0.8 = 6.4L.
Syrup left 6.4L × 5/8 = 4.0L
Add water in place of 800ml
Now you have 4L syrup: 4L water.
Replacement of syrup with water = 800ml × 2 = 1.6L.
Now, how much replacement from the original 8L in ratio?
So, 1.6/8 total replacement reduces to 1/5(ans).
Mrityunjay Yadav said:
4 months ago
At last, we have to find 8/5 litre is how many litres of 8 litres.
So it is 8/5 divide by 8 = 8/5 * 1/8.
So it is 8/5 divide by 8 = 8/5 * 1/8.
(4)
DEEPU said:
9 months ago
Let's assume Syrup reduced by R.
Then the syrup available is 5/8 and reduced to 1/2.
So, 5/8x r = 1/2.
r = 4/5.
Syrup was reduced to 4/5, so the mixture was removed 1/5.
Then the syrup available is 5/8 and reduced to 1/2.
So, 5/8x r = 1/2.
r = 4/5.
Syrup was reduced to 4/5, so the mixture was removed 1/5.
(16)
Priyanshu Chaudhary said:
1 year ago
If we remove 1 amt of the mixture -> 5/8 amt of syrup is removed.
Let's say our ans is x -> remove x amt of mixture -> (5/8)x or syrup is removed.
for both water and syrup to be in the same amount, the syrup should be 4/8 that is 1/8 of the syrup should be removed from the mixture.
Therefore (5/8)x = 1/8 => x = 1/5 =>ANSWER.
Let's say our ans is x -> remove x amt of mixture -> (5/8)x or syrup is removed.
for both water and syrup to be in the same amount, the syrup should be 4/8 that is 1/8 of the syrup should be removed from the mixture.
Therefore (5/8)x = 1/8 => x = 1/5 =>ANSWER.
(17)
Yogesh said:
2 years ago
Let's say after removing some part of the mixture.
The ratio of the remaining mixture is the same i.e. 3:5 for water to syrup.
Now consider this mixture is 8L in total (3+5).
Now once we add 2L of water in the mixture the ratio becomes 5:5 which was desired.
5+5 =10.
So we can say that even in the original mixture the quantity was 10L as 2L was removed from that.
(2L mixture removed and 2L water added).
This satisfies the condition.
Now,
The question is how much of the mixture is to be removed and replaced.
2L/10L i.e.1/5.
1/5 will be the answer.
The ratio of the remaining mixture is the same i.e. 3:5 for water to syrup.
Now consider this mixture is 8L in total (3+5).
Now once we add 2L of water in the mixture the ratio becomes 5:5 which was desired.
5+5 =10.
So we can say that even in the original mixture the quantity was 10L as 2L was removed from that.
(2L mixture removed and 2L water added).
This satisfies the condition.
Now,
The question is how much of the mixture is to be removed and replaced.
2L/10L i.e.1/5.
1/5 will be the answer.
(37)
Bhushan said:
2 years ago
We need 2 parts of water to be added to make water and syrup equal.
5 parts of water = 5 parts of syrup.
Total = 10 parts.
No of items = 2 (Water, Syrup).
= 2/10.
= 1/5.
5 parts of water = 5 parts of syrup.
Total = 10 parts.
No of items = 2 (Water, Syrup).
= 2/10.
= 1/5.
(87)
Pujitha said:
2 years ago
@Kamakshi Puri.
The question is about not removing syrup but removing a mixture of the same quantity. So, the water should be added.
The question is about not removing syrup but removing a mixture of the same quantity. So, the water should be added.
(7)
Kanishka Jha said:
2 years ago
Let
The total mixture be 8 litres.
3 l is water and 5 l is syrup.
Now we need an equal quantity to be replaced as filled.
so let the quantity be x.
5-x/3+x = 1/1.
x=1.
Part that x forms the whole quantity
= 1/5.
The total mixture be 8 litres.
3 l is water and 5 l is syrup.
Now we need an equal quantity to be replaced as filled.
so let the quantity be x.
5-x/3+x = 1/1.
x=1.
Part that x forms the whole quantity
= 1/5.
(28)
DEVINDER SINGH said:
3 years ago
Why multiply with 1/8? Please explain to me.
(68)
Atr said:
3 years ago
I didn't get this clearly. Please anyone help me.
(10)
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