Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
| Quantity of water in new mixture = |  |
3 - | 3x | + x |  |
litres |
| 8 |
| Quantity of syrup in new mixture = | |
5 - | 5x | |
litres |
| 8 |
 |
|
3 - | 3x | + x | |
= | |
5 - | 5x | |
| 8 | 8 |
5x + 24 = 40 - 5x
10x = 16
| x = |
8 | . |
| 5 |
| So, part of the mixture replaced = | |
8 | x | 1 | |
= | 1 | . |
| 5 | 8 | 5 |
Discussion:
198 comments Page 19 of 20.
Ravi said:
1 decade ago
Uttam and surender. Your answer is perfect. Kiran is wrong.
Megha said:
1 decade ago
Thanks it is really a good way to solve it.
Uttam said:
1 decade ago
Let X=volume of vessel
Y=volume of mix taken out.
Initially,
volume of water in vessel=3X/8
volume of syrup in vessel=5X/8
Y=volume of mix taken out=volume of water added.
Now,
drawn off mix may contain,
volume of water=3Y/8.
volume of syrup=5Y/8.
after mix drawn off,
volume of water in the vessel=(3X/8)-(3Y/8)=(3/8)(X-Y).
volume of syrup in the vessel=(5X/8)-(5Y/8)=(5/8)(X-Y).
After water added, volume of water in the vessel
=[(3X/8)-(3Y/8)]+Y
=[(3/8)(X-Y)]+Y.
hence from the Question,in the vessel, volume of water
=volume of syrup
[(3/8)(X-Y)]+Y=(5/8)(X-Y)
10Y=2X
Y=(1/5)*X
So volume of water should be added is (1/5)th of volume of vessel.
Y=volume of mix taken out.
Initially,
volume of water in vessel=3X/8
volume of syrup in vessel=5X/8
Y=volume of mix taken out=volume of water added.
Now,
drawn off mix may contain,
volume of water=3Y/8.
volume of syrup=5Y/8.
after mix drawn off,
volume of water in the vessel=(3X/8)-(3Y/8)=(3/8)(X-Y).
volume of syrup in the vessel=(5X/8)-(5Y/8)=(5/8)(X-Y).
After water added, volume of water in the vessel
=[(3X/8)-(3Y/8)]+Y
=[(3/8)(X-Y)]+Y.
hence from the Question,in the vessel, volume of water
=volume of syrup
[(3/8)(X-Y)]+Y=(5/8)(X-Y)
10Y=2X
Y=(1/5)*X
So volume of water should be added is (1/5)th of volume of vessel.
Kalyan said:
1 decade ago
@Mahi and Kiran
Since it is 3 parts and 5 parts...totally 8.
50% of 8 is 4 and 40% of 8 is 3.
So 60% of 8 is 5 parts.
Hope you understand.
Since it is 3 parts and 5 parts...totally 8.
50% of 8 is 4 and 40% of 8 is 3.
So 60% of 8 is 5 parts.
Hope you understand.
Vikas said:
1 decade ago
Yes mahi, something wrong with Kiran's answer.
3/8= 37.5%
5/8= 62.5%
And its not 40% and 60% as told by kiran
3/8= 37.5%
5/8= 62.5%
And its not 40% and 60% as told by kiran
Mahi said:
1 decade ago
How we will get 60% of syrup from 5 parts of syrup and 40% of water from 3 parts of water which is explained in Kiran's answer?.
Please explain in detail. Please.
Please explain in detail. Please.
Krishjlk@gmail.com said:
1 decade ago
Your great surender. Thanks a lot. Really that is very good explanation.
Instead of remembering the formulas you came with the theory.
And concept. Good excellent. Thank you for your post.
Instead of remembering the formulas you came with the theory.
And concept. Good excellent. Thank you for your post.
Krishan said:
1 decade ago
@Surender reddy. its nice approach to solve it thanks..
Bindhureddy said:
1 decade ago
@surendrareddy. Your way of explanation is good. Moreover it is easy to do.
Amuthan said:
1 decade ago
Great work Surendara Reddy.
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