Civil Engineering Mechanical Engineering Chemical Engineering Networking Database Questions Computer Science Basic Electronics Digital Electronics Electronic Devices Circuit Simulation Electrical Enigneering Engineering Mechanics Technical Drawing

Aptitude - Time and Distance - Discussion

@ : Home > Aptitude > Time and Distance > General Questions - Discussion

"Hold a true friend with both hands."
- (Proverb)
5.

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

 [A]. 9 [B]. 10 [C]. 12 [D]. 20

Explanation:

Due to stoppages, it covers 9 km less.

 Time taken to cover 9 km = 9 x 60 min = 10 min. 54

 Kanmani said: (Tue, Aug 17, 2010 08:22:23 AM) How to get 9 km?

 Sundar said: (Tue, Aug 17, 2010 08:51:39 AM) It is obtained by 54 kmph - 45 kmph = 9 kmph.

 Girishkumar said: (Wed, Aug 18, 2010 12:29:02 PM) How did 9/54 come?

 Shaju said: (Sat, Sep 11, 2010 05:54:51 AM) Hey its 54 kmph and 45 kmph. Can you explain how you got 9 km by subtracting the speeds of bus at different circumstances?

 Nitesh85 said: (Sat, Oct 9, 2010 06:12:27 AM) @Mr.Shaju 54 - 45 = 9 km is absolutely correct because we are calculating relative results.

 Nitesh Nandwana said: (Sat, Oct 9, 2010 06:20:20 AM) @Girishkumar hi itz simple. Because 54km in 1 hour. So 1 km in 1/54 hour. So 9 km in 9* (1/54) *60 min (1 hour = 60 min).

 Sam said: (Tue, Oct 19, 2010 12:31:37 PM) Why to consider 54 rather than 45?

 Rojalin said: (Wed, Nov 10, 2010 09:39:02 AM) Why to consider 54 rather than 45?

 Ranjit said: (Sat, Nov 13, 2010 01:13:41 AM) First we have to see what they asked. For how many minutes does the bus stop per hour. For that we have to consider the value 54 (exclude stoppages) ie. , if we consider the value 45 the bus has been already stopped so we are considering value 54.

 Jaya said: (Tue, Nov 23, 2010 07:00:20 AM) The easy method: For 1 hour the bus travels for 54 km then for one min its 54/60=0.9km. So if the bus stops for one minute it travel 0.9 km less so if the bus travels 9 km less then it might stopped for 10 min.

 Krishna said: (Fri, Dec 17, 2010 06:34:31 AM) Excellent explanation thank you JAYA. Thanks a lot.

 Ravindhar Reddy said: (Fri, Dec 17, 2010 10:24:39 PM) great explanation . thank you jaya.

 Ankit said: (Thu, Dec 23, 2010 03:39:52 PM) Great jaya. !

 Sumit said: (Tue, Feb 8, 2011 03:18:56 AM) Jaya your are great.

 Kushal said: (Sun, Feb 13, 2011 08:39:57 AM) 60 mins(1hr)--------------->54kms ???mins--------------------->9kms solving we get the ans:-)

 Sheela M B said: (Tue, Mar 29, 2011 02:04:47 PM) Well thought by Jaya ans Kushal. Gr8 guys!!

 Simanta Chatterjee said: (Mon, Apr 25, 2011 06:03:56 AM) Awesome kushal. Hats off.

 Hari said: (Tue, May 24, 2011 03:44:05 AM) Excellent kushal. This method is easy.

 Reeta said: (Mon, Jun 6, 2011 08:46:12 AM) Great jaya.

 Rahul said: (Mon, Jun 27, 2011 12:08:46 PM) How did u get as 9 km, as they have subtracted the two speeds...!!!! if they have subtracted them it would result as 9 km/hr!!!! Then hw s it possible to get the time...???? May be the question is wrong..!!!!

 Nivi said: (Thu, Jul 7, 2011 04:41:36 AM) How 9/54 came. Please explain.

 Rn Pandian said: (Tue, Jul 12, 2011 03:36:21 AM) Excellent Kushal. Hats off........

 Rukshana said: (Fri, Jul 22, 2011 07:23:57 PM) Rahul....Question is right only...Actually without stoppages it cover 54 but with stoppages it cover only 45...so only we need to subtract...to get the speed without stoppages..so 54-45=9..Then we having speed with stoppages ..so only considering 9\54 then we need to get min so mul by 60..now got?

 Swetha said: (Wed, Aug 10, 2011 12:51:56 PM) I have the same doubt that what rahul having..if we subtracting two speeds ,then we will get difference in speed na? how we got the distance 9 km?

 Anoo said: (Wed, Aug 10, 2011 01:01:15 PM) 54 kms in 1 hour..but in 1 hour it travelled only 45 kms..9 kms less.. 1 hour-54 kms ??? - 9kms 1x9/54 = 1/6 hour = 10 minutes

 Supreeth said: (Mon, Aug 29, 2011 02:23:09 PM) Can't we solve this question like this? if no why? We now that, Displacement(S) = Velocity(V) * Time taken(t). ie,s=vt. consider 1st condition.. Let the distance travelled by bus be 'x'm. therefore,x=54t.(without stoppage).......(1) From 2nd condition.. x=45(t+y)........(2) (y=total stoppage time) Dividing 1 & 2 n solving we get bus stops for 12 mins in 1 hour.

 Piyus said: (Mon, Aug 29, 2011 06:37:39 PM) Why it will be 10 minutes instead of 12 minutes ?

 Sumit said: (Mon, Oct 10, 2011 01:23:37 PM) The time taken by the bus for i k.m is 60/54=1.11 min so if the bus travels 9 k.m less due to stoppage then the ans will be =1.11*9=10 min.

 Chetna said: (Tue, Nov 1, 2011 09:27:57 AM) Why we consider only 54 but not 45?

 Dhruv said: (Tue, Nov 8, 2011 11:26:38 AM) Good explanation jaya.

 Ajit said: (Sat, Nov 12, 2011 08:00:33 AM) Simple is that you hav to calculate the wasted time=time taken by bus to cover 9kms). In one min it covers 0.9 kms. For 9kms-?min. You get 10min.

 Kasi said: (Wed, Jan 4, 2012 09:27:20 AM) Good explanation kushal :)

 Krishn said: (Sat, Jan 21, 2012 11:05:05 AM) I still didn't understand. If 54km - 45 km = 9 km. That is speed reduces by 9 km/hr. So 60/9 = 20/3 per min...now how do i proceed next?

 Shro said: (Sat, Feb 18, 2012 08:10:33 PM) Hey somebody explain it clearly 54km/hr-45km/hr=9km/hr Why to consider only 9km? why not 9km/hr? The answer is clearly 9km /hr. Then why to convert it into minutes? it should be only 9/54= 1/6 or say 0.16

 Denis said: (Mon, Mar 5, 2012 05:07:42 PM) Thanks Kushal.

 Kunal said: (Fri, Mar 30, 2012 03:38:16 PM) If the bus doesn't stop for an hour it travels 54 km at a constant speed of 54kph. But it stops for some time 't' and covers 45 km in the remaining (60-t) mins at 54kph. 45 = (60-t) * (54/60) => t=10mins.

 Afsar said: (Tue, Apr 3, 2012 09:02:47 AM) How it take 9km. ? It is because there is no time limit given so. We take reference time 1hr. And each having same time. So distance=speed*time.

 Harshita said: (Tue, Apr 17, 2012 07:57:07 PM) Hi. Please tell what is wrong in the following approach? because I'm not getting the right answer by this. 54 km/hr means in 1hr it will cover 54km. Now if it stops of x hr the the new speed. 45=54/ (1+x). So x=9/45 hr= (9/45) 60 min. =12 min?

 Pratik said: (Sun, Apr 22, 2012 04:39:06 PM) Let us suppose 10 min is the ans.. Let the distance covered be 54km. Time 1 hr without stoppage. Then 54/1 = 54 kph.. With stoppage of 10 min= 1/6 hr= 0.1667 hr 54/(1+0.1667)= 46.28 kph --------------------------------- Let 12 min be the ans With stoppage 0f 12 min=1/5hr=0.2hr 54/(1+0.2)= 45 kph.

 Chinmayee said: (Thu, May 3, 2012 03:35:37 PM) Why we take 54 instead of 45 ? please solve my question.

 Suresh Khichee said: (Wed, Jun 20, 2012 12:16:14 AM) D = S*T. D = 54/1 * T ....(1) T is time taken by bus without stoppages. D = 45/1 *( T + S ) ...(2) where S is time taken by stoppages. By (1)& (2) 54*T = 45*T + 45*S 54*T - 45*T = 45*S 9*T = 45*S or 9/T = 45/S so ratio of T/S = 45/9 T/S = 5/1 {T=time ,S= time of stoppage } T:S ::5:1 shows that In 6 minute(5+1) bus takes 1 minutes for stoppage. So In 60 minutes bus will take 10 minutes stoppage.

 Murali said: (Sat, Jan 19, 2013 06:19:59 PM) Excluding stoppages= (difference of speeds/excluding Stoppage) *60mins. = (54-45/54) *60mins. = (9/54) *60mins. = (1/6) *60mins. =10mins.

 Akriti said: (Thu, Mar 21, 2013 07:35:35 AM) Here speed is given - 54 (excluding stoppages), 45(including ). Time taken at stoppages -d/t. So 9 kmph, distance - 9*60. 540/54 because (distance /time), we got 10min.