Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
206 comments Page 2 of 21.
Vipin ydv said:
2 years ago
Solution:
S1 ---> 54 kmph,
S2 ---> 45 kmph
S1 means in 60 min bus travel 54 km.
S2 means 60-t(required time).
S2(45) -----> (60-t)min.
1 min -----> s2/60 - t.
60 min -----> s2 * 60/60 - t = s1.
t = 45 * 60/54,
t = 10 min.
S1 ---> 54 kmph,
S2 ---> 45 kmph
S1 means in 60 min bus travel 54 km.
S2 means 60-t(required time).
S2(45) -----> (60-t)min.
1 min -----> s2/60 - t.
60 min -----> s2 * 60/60 - t = s1.
t = 45 * 60/54,
t = 10 min.
(4)
Jason Valentine said:
2 years ago
Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.
(23)
PARAS FULARA said:
2 years ago
Consider the covers 54km & 45km in an hour without stoppage and with stoppage respectively. Since he covers 9 km less in stoppage.
His normal speed without stoppage is 54 km/h.
So, the time required to cover this distance is 9/54 hours i.e. 1/6 hour or 10 minutes.
So, he waited for 10 minutes in stoppage.
His normal speed without stoppage is 54 km/h.
So, the time required to cover this distance is 9/54 hours i.e. 1/6 hour or 10 minutes.
So, he waited for 10 minutes in stoppage.
(15)
Kaviprema k said:
2 years ago
Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.
(15)
Pramod said:
2 years ago
@Naren.
Because 54Kmph was the actual speed and 45Kmph was the speed after stoppage.
Because 54Kmph was the actual speed and 45Kmph was the speed after stoppage.
(3)
Milli said:
2 years ago
54kmh means it travels 54 kms in one hour when the train runs continuously in that hour. However including stoppages the train travels only 45 km in one hour. Thus in one hour train travels 9 km less due to stoppages.
Thus the time the train stops in an hour is the time it would have used to travel 9kms with the speed of 54kms, which when converted to minutes is equal to 10.
Thus the time the train stops in an hour is the time it would have used to travel 9kms with the speed of 54kms, which when converted to minutes is equal to 10.
(9)
Naren said:
2 years ago
I can't understand why we have taken 54km/hr for calculation. Why not 45km/hr? Anyone, please clarify it.
(25)
Agan NeyanR said:
2 years ago
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9 x 60 min = 54.
Time taken to cover 9 km = 9 x 60 min = 54.
(6)
Yen said:
2 years ago
@All.
Here is my solution;
For me, in 1 hour the bus runs 54 km by the speed of 54km/h excluding stops.
But because of stop time, it runs by a speed 45km/h.
That means 54 km/ times = 45 ( km/h).
So the total times needed is 54/45 = 6/5 h,
And stop time is 6/5 -1 = 1/5h = 12 minutes.
Here is my solution;
For me, in 1 hour the bus runs 54 km by the speed of 54km/h excluding stops.
But because of stop time, it runs by a speed 45km/h.
That means 54 km/ times = 45 ( km/h).
So the total times needed is 54/45 = 6/5 h,
And stop time is 6/5 -1 = 1/5h = 12 minutes.
(9)
Niharika said:
2 years ago
Fast speed-slow speed/Fast Speed = 54-45/54 = 1/6.
To convert into minutes =1/6 * 60 = 10.
To convert into minutes =1/6 * 60 = 10.
(59)
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