Hi every one
here this problem is a bit difficult to understand. let me give u an another example then we will come to this.
let c.p. of 1 article is Rs. 4 and
let s.p. of 1 article is Rs. 5
now c.p. of 20 article is 20*4=80
and s.p.of 16 article is 16*5=80
the first line of the question said these r equal that is Rs. 80
now come to our problem above.
let c.p of 1 article is Rs.1
here given that c.p. of 20 article is equal to s.p. of x article
so let us calculate c.p. of 20 article=Rs 20
hence s.p. of x article is Rs. 20
so s.p. of 1 article =20/x
profit on one article= (20/x)-1
% profit=((20/x)-1)*100)/1=25
hence x=16
Sid said:
(Fri, Sep 24, 2010 06:58:36 AM)
Thanks sanjeet, nice explanation.
Sarath said:
(Fri, Oct 15, 2010 10:38:20 AM)
Can you explain me about the assumptions it makes me difficult to understand?
Anbu said:
(Sat, Oct 23, 2010 08:32:39 AM)
Sanjeet your explanation is very good.
Aamir said:
(Fri, Nov 12, 2010 09:52:47 AM)
I cant undrstnd this question plz any help me to undrstnd this
Chetan said:
(Fri, Nov 12, 2010 12:29:38 PM)
Hi guys,
20 article C.P = 100rs(say)
Note: When given profit percentage, he calculates it only after selling all goods.
So 20 articles S.P = 125 (SINCE PROFIT PERCENT =25%)
now consider only S.P
125 rs --->20 articles
100 rs --->? articles
100*20/125=16
That is it simple.
Vasanthi said:
(Sat, Nov 13, 2010 08:39:26 AM)
Sanjeet your explanation is very nice.
Indu said:
(Sun, Nov 21, 2010 01:37:55 AM)
Very nice and simple explanation sanjeet. Thanks.
Anjali&Amp;Sandhya said:
(Sat, Nov 27, 2010 06:25:55 AM)
Chetan nice answer anjali and sandhya.
Ruby said:
(Thu, Dec 2, 2010 12:56:34 PM)
Sanjee how does the profit of one article will be (20/x) -1.
Chinni said:
(Tue, Dec 7, 2010 05:31:33 AM)
profit=s.p-c.p
hence cost of 1 article=1
s.p of 1 article=20/x
profit=(20/x)-1
Rupesh said:
(Sat, Dec 18, 2010 12:45:35 AM)
Then where is the solution of 25%.
Priya said:
(Tue, Dec 21, 2010 02:22:32 AM)
How profit is given as 20-X?
Mukul said:
(Mon, Dec 27, 2010 12:16:28 PM)
@priya :- when u got s.p of x article = Rs. 20 and c.p of 1 article is re.1 so for 'x' article c.p will be Rs. x .
now s.p - c.p = profit
hence 20 - x . = profit .
Parth said:
(Tue, Jan 4, 2011 10:20:57 PM)
Thanx chinni and sanjeet awsum xplanation!
Vignesh.R said:
(Thu, Jan 6, 2011 01:43:34 PM)
Chetan! your explanation is cute and understandable.
Jacky said:
(Sat, Jan 15, 2011 01:42:05 AM)
Sanjeet kumar gives the nice explanation.
which is easly understandable.
thanks frnd.
if 25% profit given u can take the example of c.p is 4 and s.p is 5.
20*4=x*5
x=16
Sumit Yadav said:
(Sun, Jan 16, 2011 12:25:21 PM)
@chetan
Its Nice. You realy did well, you make this problem very simply.
Vishal said:
(Tue, Feb 1, 2011 07:02:42 AM)
priya...
in general form.
let the cost of 20 article = y rs
so cost of 1 article= y/20rs
and cost of x article = xy/20
so the profit= price-sailing price/sailing rate
25=(y-x*y/20)/(x*y/20)
by solve this u got 16 answer
Assume, CP of 1 article is Re.1,
CP of X artilcles is rs.X..............B
CP(20 Articles)=rs.20..................C
So A becomes,
rs.20 = SP(X articles).................D
c.p of 20 articles= s.p of x articles .........1
s.p=((100+profit%)/100)*c.p
hence from the above values we get
s.p=(5/4)c.p
substitute in 1 we get
X=16
Prathyusha said:
(Wed, Mar 2, 2011 02:27:46 AM)
Sundar and sanjeet explanation was nice!.
Good work guys!.
Thanku.
Kumar said:
(Tue, Apr 12, 2011 02:12:32 PM)
How it was come by using 2000..i cant understand plz explain detaily
Pankaj said:
(Wed, Apr 27, 2011 03:39:58 AM)
How to solve ( (20/x-1) x100) /25?
Kailash said:
(Sun, May 1, 2011 02:23:47 AM)
Profit=x-y/y *100
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
Surya said:
(Tue, May 17, 2011 08:00:00 AM)
Very nice explanation thanks to snnjeet.
Priyanka said:
(Tue, May 24, 2011 03:03:38 AM)
How 20-x sir ?
Vivek said:
(Thu, Jun 2, 2011 02:31:04 AM)
Thank for your explanation sanjeet it is so easy to understand after you explain, I like this site very much.
Roopa said:
(Fri, Jun 24, 2011 10:25:07 AM)
Really nice to join your discussion.
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
Vinu said:
(Thu, Jul 7, 2011 11:03:21 PM)
Hi kailash awesome shortcut.
Vinay said:
(Tue, Aug 2, 2011 09:58:53 AM)
Please Try to Solve the Problems without any Formulas. Understand the Problem and solve it and your own.
Umesh said:
(Fri, Aug 5, 2011 03:16:21 PM)
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
===> LET CP BE Rs 100
CP OF 20 =2000
SP OF 20 =2000*1.25(PROFIT) = 2500
SP OF 01 =2500/20 =125
THERFORE ANSWER = 2000/125 =16
OR
CP *20 =SP *X
PUT SP=1.25CP
NOW, CP*20=1.25CP*X
CANCEL CP FROM BOTH
X = 20/1.25 =16
Nikhil said:
(Sun, Aug 7, 2011 12:03:43 AM)
Awesome explanation chetan!thanx:).
Rashmi Shukla said:
(Fri, Aug 19, 2011 06:18:28 PM)
Clear explanation sangeet thanks :).
Kapil said:
(Tue, Aug 23, 2011 12:01:00 AM)
@Sanjeet
Why we take selling prize = 5 ?
Nj. said:
(Tue, Aug 23, 2011 09:10:27 PM)
Nice Explanation Umesh!!!!! Good Job!
Vikas said:
(Sat, Sep 3, 2011 12:26:01 PM)
Hi Guys,
U can use a very simple method, i.e.,
Suppose,
C.P of 1 item = Rs.100
So C.P of 20 item = Rs.2000
Now profit is 25% so,
s.p of 1 Item = Rs.125 {125% of C.P}
s.p of x Item = 2000 {= C.P of 20 Items}
Therefor number of x item = 2000/125
= 16 Ans.
Dharmendra said:
(Sat, Sep 3, 2011 10:38:26 PM)
Suppose c.p. of 1 article is Rs. 1
so c.p. of x article is Rs. x.........(1)
now s.p. of x articles is 20.........from the question....(2)
now profit is s.p-c.p = 20-x .............(3)
now use the formula gain%=gain*100/c.p
25=(20-x)*100/x ...........(1)+(3)
now solve it.
2000 - 100x = 25x