Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
15
16
18
25
Answer: Option
Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

20 - x x 100 = 25
x

2000 - 100x = 25x

125x = 2000

x = 16.

Video Explanation: https://youtu.be/sidqvjUoZxY

Discussion:
361 comments Page 1 of 37.

Ragavi P said:   2 weeks ago
Let CP be 100.
CP of 20 articles = SP of x articles.
CP * 20 = SP * x.
100 * 20 = SP * x.
2000 = SP * X ---> equation 1.

To find SP :
SP = CP( 1 + Profit%/100).
SP = 100(1 + 25/100).
SP = 100 (125/100),
Hence SP =125 ---> equation 2.
Substitute equation 2 into 1.
2000 = 125 * x.
x = 16.
(3)

Dinesh said:   2 months ago
How are we assuming that per article sold 125%. Aren't the total SP is 125%?

Anyone, please explain.
(3)

Niranjan said:   3 months ago
I am not getting this. Anyone, help me.
(3)

Sourav Gorain said:   3 months ago
CP = 100/article.
SP = 125/article, as we know the profit% is 25%.

Therefore,
CP of 20 articles = SP of x articles.
=> 20 * 100 = x * 125.
=> x = 4 * 4.
=> x = 16 (Ans).
(48)

Madhuri said:   7 months ago
CP = always 100%.
cp + sp = 125.
20 × 1000/125.
= 16.
(21)

Banusuvarna said:   11 months ago
I do not understand the answer. Anyone, please explain to me.
(18)

Abir Saha said:   1 year ago
In ratio method,

20 c.p = x s.p
or,c.p:s.p = x:20
or, 20-x/x = 25/100

And solution is 16 RS.
(16)

Shiyaam said:   1 year ago
So simple;

Let ,Cp = 100.
25%proft = 25.

So, SP = 125,
100 × 20 = 125x,
X = 16.
(107)

Surendar said:   1 year ago
Let assume cp = 100,
Profit is 25%.
sp = 125.
cp 20 = spx,
sp/cp = 20/x,
125/100 = 20/x.
So, the final answer is 16.
(105)

Sree said:   1 year ago
Deriving formula:

S.P = [100 + gain% / 100 ] x C.P.
S.P is x.
C.P is 20x, so one CP is x/20,
x = 125/100 x (x/20),
x = 125x/2000,
2000x = 125x,
= 16.
(14)


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