Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 13)
13.
On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
Sunday
Thursday
Tuesday
Friday
Answer: Option
Explanation:

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.

But, 8th Dec, 2007 is Saturday.

8th Dec, 2006 is Friday.

Discussion:
15 comments Page 1 of 2.

Greeshma said:   1 week ago
When the year becomes less than, we should subtract like 2007 from 2006.

When the year becomes greater, we should add like 2006 from 2007.

Purna said:   4 years ago
Anyone could tell me why we are not considering 2007's odd day, why only 2006's odd day Is considered?
(3)

Suzu said:   5 years ago
Can anyone explain me why we are subtracting when it says beyond 1? And in another q when it says beyond they are adding.
(3)

Bmh said:   6 years ago
When we should subtract when should add, I'm not getting.
(3)

Megha said:   7 years ago
How come it has 1 odd day?

Anyone please explain.
(3)

Ravi said:   8 years ago
Step1:No.of odd days 2000=0.
Step2:No.of odd days 2001 to 2005=2+4=6.
Step3: No.of odd days-jan to Dec-8=342 (48 weeks+6 days=6.

Total No.of odd days=0+6+6=12/7=5 odd days 5 odd number is Friday. The answer is Friday.
(4)

Shaikh aasif said:   9 years ago
The tricks say;

Find the difference of year 2007-2006 = 1.
And no of leap year between this two year is zero then,
0+1=1.
Then,
Saturday + 1 day = Sunday.
(4)

Rithika said:   9 years ago
Hi friends!

Does it is necessary the question should be like from "8 DEC" 2001 TO "8DEC" 2005?

Can the question be like "8 dec"2001 to "10 dec" 2005?

Kalyan said:   1 decade ago
Please explain how come 1 odd day?

Jagbir singh said:   1 decade ago
There will be 2 odd days in 8 december 2006 to 31 december 2006.

31-8 = 23/7 = remainder = 2.

How there will be 1 odd days?
(1)


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