Verbal Reasoning - Direction Sense Test - Discussion
Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 7)
7.
Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
Answer: Option
Explanation:
Discussion:
43 comments Page 4 of 5.
Aditya said:
1 decade ago
It's simple,
Both of them being on the opposite side of a main road (facing each other) 150 km apart.
One of them moves 25km, then diverts for 15 km (no need for calculation) and then moves 25 km and then back to main road, whereas the other person moves 35km from opposite side.
So the distance travelled by one is 25 + 25 = 50 km and the other is 35 km. Distance between them currently is 150 - (50 + 35) = 65km.
Both of them being on the opposite side of a main road (facing each other) 150 km apart.
One of them moves 25km, then diverts for 15 km (no need for calculation) and then moves 25 km and then back to main road, whereas the other person moves 35km from opposite side.
So the distance travelled by one is 25 + 25 = 50 km and the other is 35 km. Distance between them currently is 150 - (50 + 35) = 65km.
Devyanshi said:
1 decade ago
Whether both the cars move towards each other or away from each other is not given. So the can't be correctly given.
Anushka said:
1 decade ago
Why we consider the 15 km?
Vinitha said:
1 decade ago
Can any one explain why 15 km is not taken for consideration?
Ratnesh pareek said:
1 decade ago
Why 15 is not added? Can anyone explain please?
Surya said:
1 decade ago
Can anybody give detailed answer step by step?
Neha said:
1 decade ago
Why 15 is not added?
Nitika Kapoor said:
1 decade ago
It is clearly mentioned in the question that the car after travelling goes BACK to the main road! Then how can we do (25+25+35).
Since it is given that the total distance is 150 km between the two cars at starting position, and that the other car has travelled 35 km ON THE MAIN ROAD, then how can we make FE with CD, it should be made with AB (the path of the first car on the main road).
Therefore, it will be:
150-(AB+FE).
= 150-(25+35).
= 150-60.
= 90.
Since it is given that the total distance is 150 km between the two cars at starting position, and that the other car has travelled 35 km ON THE MAIN ROAD, then how can we make FE with CD, it should be made with AB (the path of the first car on the main road).
Therefore, it will be:
150-(AB+FE).
= 150-(25+35).
= 150-60.
= 90.
Kakoli said:
1 decade ago
@Sravya.
15 km is an unnecessary data here. Do it as simply as possible.
At the starting point distance between them is 150 km. While the first car passed 5o km at the same time second car passed 35 km. Now, distance between them {150- (50+35) }= 65.
Hope you get it.
Thanks.
15 km is an unnecessary data here. Do it as simply as possible.
At the starting point distance between them is 150 km. While the first car passed 5o km at the same time second car passed 35 km. Now, distance between them {150- (50+35) }= 65.
Hope you get it.
Thanks.
Sravya said:
1 decade ago
Now A travels total 50km. Because he travels extra 15 km to reach the main road. It is additional to reach the main road. He travels directly another 25 km.
So 15 km is not considered.
So 15 km is not considered.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers