Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 2 (Q.No. 2)
Directions to Solve
Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
2.
If the odd numbered dice have even number of dots on their top faces, then what would be the total number of dots on the top faces of their dice?
Answer: Option
Explanation:
Odd numbered dice are : (II), (III) and (V)
No. of dots on the top faces of these dice are 2, 2 and 4 respectively.
Required total = 2 + 2 + 4 = 8
Discussion:
16 comments Page 2 of 2.
Avinash sonawane said:
8 years ago
I =5/2
II =5/2
III =4/3
Answer =14/7
So, 14.
II =5/2
III =4/3
Answer =14/7
So, 14.
Jai said:
8 years ago
I don't understand the logic.
Please help me.
Please help me.
(1)
Jitendra said:
8 years ago
5+3+2=10 can be answer. Then why not 10 can be the answer?
Deepansh said:
6 years ago
2+2+4=8 is correct
According to question odd no. dice like (I,II,III) top should be even and sum between opposite face 7.
Now in 1st dice, you can see 3 and 6 faces so their opposite face should be 4 and 1 respectively. only top and bottom place are left so 2 should come on top which is even and bottom should be 5 which is 2+5=7. A/c question we will select even only = 2.
similarly in 3rd dice 6 and 4 face so opposite face should be 1 and 3 respectively.
now top should be again 2 which is even = 2.
similarly, in 5th dice 1 and 5 faces are given so their opposite face is 6 and 2 respectively.
Now the top should be 4 which is even = 4.
ANS = 2+2+4 = 8.
According to question odd no. dice like (I,II,III) top should be even and sum between opposite face 7.
Now in 1st dice, you can see 3 and 6 faces so their opposite face should be 4 and 1 respectively. only top and bottom place are left so 2 should come on top which is even and bottom should be 5 which is 2+5=7. A/c question we will select even only = 2.
similarly in 3rd dice 6 and 4 face so opposite face should be 1 and 3 respectively.
now top should be again 2 which is even = 2.
similarly, in 5th dice 1 and 5 faces are given so their opposite face is 6 and 2 respectively.
Now the top should be 4 which is even = 4.
ANS = 2+2+4 = 8.
(7)
Yadav said:
3 years ago
First, the given is all dice are standard dice because the sum of any opposite side is = 7.
So, by this, we can find all the missing spots.
All standard dice have the same value which are;
1. Top = 1.
2. Bottam = 6.
3. Right = 4.
4. Left = 3.
5. Front = 2.
6. Back = 5.
So, now. If you top (1) + bottam (6) = 7, right (4) + lift (3) = 7, front (2) + back (5) =7. By this you can fill the the blankspots.
So, by this, we can find all the missing spots.
All standard dice have the same value which are;
1. Top = 1.
2. Bottam = 6.
3. Right = 4.
4. Left = 3.
5. Front = 2.
6. Back = 5.
So, now. If you top (1) + bottam (6) = 7, right (4) + lift (3) = 7, front (2) + back (5) =7. By this you can fill the the blankspots.
(2)
Jyoti bhardwaj said:
3 years ago
I don't think that 8 is correct. Because it says take odd number so we have to take an odd number.
I) we see 3 & 6 is shown, which means its opposite numbers are 4 & 1. The erase portion is 2 & 5. Now check the third dice and fifth dice.
III) - 5&2, dice.
(V) -3&4, dice.
From this we take odd no. :- 5 + 5 + 3 = 13 is answer.
I hope it's helpful for all.
I) we see 3 & 6 is shown, which means its opposite numbers are 4 & 1. The erase portion is 2 & 5. Now check the third dice and fifth dice.
III) - 5&2, dice.
(V) -3&4, dice.
From this we take odd no. :- 5 + 5 + 3 = 13 is answer.
I hope it's helpful for all.
(3)
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