Verbal Reasoning - Dice - Discussion

Discussion Forum : Dice - Dice 2 (Q.No. 2)
Directions to Solve

Six dice with upper faces erased are as shows.

The sum of the numbers of dots on the opposite face is 7.


2.
If the odd numbered dice have even number of dots on their top faces, then what would be the total number of dots on the top faces of their dice?
8
10
12
14
Answer: Option
Explanation:

Odd numbered dice are : (II), (III) and (V)

No. of dots on the top faces of these dice are 2, 2 and 4 respectively.

Required total = 2 + 2 + 4 = 8

Discussion:
16 comments Page 1 of 2.

Deepansh said:   6 years ago
2+2+4=8 is correct

According to question odd no. dice like (I,II,III) top should be even and sum between opposite face 7.

Now in 1st dice, you can see 3 and 6 faces so their opposite face should be 4 and 1 respectively. only top and bottom place are left so 2 should come on top which is even and bottom should be 5 which is 2+5=7. A/c question we will select even only = 2.

similarly in 3rd dice 6 and 4 face so opposite face should be 1 and 3 respectively.
now top should be again 2 which is even = 2.
similarly, in 5th dice 1 and 5 faces are given so their opposite face is 6 and 2 respectively.

Now the top should be 4 which is even = 4.
ANS = 2+2+4 = 8.
(7)

Jyoti bhardwaj said:   3 years ago
I don't think that 8 is correct. Because it says take odd number so we have to take an odd number.

I) we see 3 & 6 is shown, which means its opposite numbers are 4 & 1. The erase portion is 2 & 5. Now check the third dice and fifth dice.

III) - 5&2, dice.

(V) -3&4, dice.

From this we take odd no. :- 5 + 5 + 3 = 13 is answer.

I hope it's helpful for all.
(3)

Yadav said:   3 years ago
First, the given is all dice are standard dice because the sum of any opposite side is = 7.

So, by this, we can find all the missing spots.

All standard dice have the same value which are;

1. Top = 1.
2. Bottam = 6.
3. Right = 4.
4. Left = 3.
5. Front = 2.
6. Back = 5.

So, now. If you top (1) + bottam (6) = 7, right (4) + lift (3) = 7, front (2) + back (5) =7. By this you can fill the the blankspots.
(2)

Bhumi choudery said:   10 years ago
I did not understand the question of dice 2 please explain.
(1)

Jai said:   8 years ago
I don't understand the logic.

Please help me.
(1)

Ramphal said:   1 decade ago
How dice 11 is odd number?

Kanwaldeep said:   1 decade ago
Odd numbered dice are : (II), (III) and (V)

Here I did not understand how II is the odd one?

HafzanaSamsudeen said:   1 decade ago
I also did not understand how II is the odd one. ? & I also can't understand the question.

Santosh said:   1 decade ago
Here odd numbered dice means sum of faces in the figure should be even. Then we get 3, 4, 5 figure as odd numbered dice.

No. of dots on the top faces of these dice are 2, 6 and 4 respectively.

Required total = 2+6+4 = 12.

Therefore 12 is the answer.

Debabrata said:   1 decade ago
@To all folks.

First of all as mentioned in the question that "The sum of the numbers of dots on the opposite face is 7. So therefore, the pattern is (1, 6) (2, 5) (3, 4) or vice verse.

Therefore in dice (i) , we see 3 & 6 is shown, that means its opposite numbers are 4 & 1. The erase portion is 2 & 5.

Similarly for dice dice (ii) - 6 & 1, dice (iii) - 5&2, dice (iv) - 6, 1, dice (v) -3&4, dice (vi) - 6&1.

So A/Q No 1- it is 6 +6+6 =18.

A/Q No2- it is taken from dice (i), dice (iii) & dice (v) -2+2+4=8.

And the other process go on like this.

Hope this will help.


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