Verbal Reasoning - Dice - Discussion

Please tell the rules of dice type II.

You told that even numbered dice have even number of dots on their top faces if we set it as four it should be 12 but you take it as 6.

Can we take 4 or not?

You told that 2, 4 & 6 dice have even number of dots on their top faces then here should be one option with value 6 b'cz 2 is also even number & here can be answer 12 also.

If your answer is right then explain it that why are you taking 6 dots in one dice?.

When you observe carefully you see only 4, 5, 2, 3 will on the sides and the remaining two nos 6, 1 are left for us to deal with and amongh these two only 6 is even that explains every ones question.

I think so, ans is 10.

No. Of dots on dice II = 2.

No. Of dots on dice IV = 6 (as 4 and 2 at adjacent).

No. Of dots on dice VI = 2.

Yeah I got the answer.....

Let us read the question very carefully....

1) dices are not different kind
2)the given condition is sum of number of dots on bottom faces(opposite to erased upper faces) is 7.

According to above second point we have only one possibility i.e.
1+1+1+1+2+1=7

Because the fifth dice have number 1 dot on forward face so the bottom face value should be 2.

Hence bottom face number of
1st dice=1
2nd dice=1
3rd dice=1
4th dice=1
5th dice=2
6th dice=1

And coming to problem adjacent faces of number 4 are 1,2,5,6(remember that number 1 is at bottom).

So number 4 is opposite to number 3.

Now consider fourth dice,we have the following numbers on the
forward face=2
right face=4
left face=3 (since 4 is opposite to 3)
bottom face=1 (which we got earlier from given condition)

Now we left with top and backward faces.
From given data even numbered dices have only even number on their top faces. So,we left only with one even number 6.

Therefore
top face=6
backward face=5. and 1 is opposite to 6

Second,fourth,sixth dices have 1 on bottom face.so they all have number 6 on their top.

Hence total number of dots on thier top faces is 6+6+6 = 18.

Anand kumar your great.

Yup great explanation anand:).

Well done Anand. :-)

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