Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 2 (Q.No. 1)
Directions to Solve
Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
1.
If even numbered dice have even number of dots on their top faces, then what would be the total number of dots on the top faces of their dice?
Answer: Option
Explanation:
Even numbered dice are: (II), (IV) and (VI)
No. of dots on the top face of (II) dice = 6
No. of dots on the top face of (IV) dice = 6
and No. of dots on the top face of (VI) dice = 6
Therefore Required total = 6 + 6 + 6 = 18
Discussion:
33 comments Page 4 of 4.
Prashanthraj said:
2 years ago
Here even number dice are=2,4,6.
(Note:The sum of the numbers of dots on the opposite face is 7.)
if we take dice2...in there 5and 4dots;
So;
5 + 2 = 7.
4 + 3 = 7.
Then 2dice have 2 + 3 = 5.
If we take dice4; in there 2 and 4 dots.
So;
2 + 5 = 7
4 + 3 = 7.
Then 4dice have 5 + 3 = 8
**If we take dice6 in there 4and 5
So.
4+3=7
5+2=7.
Then dice6 have 3+2=5
No add three even numbers (2,4,6) dice
We get 5+8+5=18
Hence proved.
(Note:The sum of the numbers of dots on the opposite face is 7.)
if we take dice2...in there 5and 4dots;
So;
5 + 2 = 7.
4 + 3 = 7.
Then 2dice have 2 + 3 = 5.
If we take dice4; in there 2 and 4 dots.
So;
2 + 5 = 7
4 + 3 = 7.
Then 4dice have 5 + 3 = 8
**If we take dice6 in there 4and 5
So.
4+3=7
5+2=7.
Then dice6 have 3+2=5
No add three even numbers (2,4,6) dice
We get 5+8+5=18
Hence proved.
(14)
Sai nikhil Jallepalli said:
1 year ago
Guys here's a Straightforward explanation!
Key points(Rules) from the question:
1) Opposite sides sums up to 7 [{1,6}, {2,5}, {4,3}]
2) Select Even index dice [ dice2, dice4, dice6 ] & if their top side face have only even number
then how many dots are total in the top face(which are even) of even index dice?
3) Total means summing
4) No of dots on a face = Numeric representation of those dots.
Take dice2
Use rule (1):
5<->2 -> {5 is in front then opposite is 2 which will be on back}
4<->3 -> {4 is in the right then the opposite is 3 which will be on the left}
1<->6 ----> only top face for even index dice = 6 {question said even is always on top so remaining even number is 6}
select 6
take dice4
use rule (1):
5<->2 {2 is on face then opposite 5 will be on back}
4<->3 {4 is on the side then on another side, there will be 3}
1<->6 ----> only top face for even idex dice = 6 {question said only even will be on top & remaining choice for even is 6}
select 6
take dice4
use rule (1):
5<->2
4<->3
1<->6 ----> only top face for even index dice = 6.
select 6 -> same reason as above;
Perform total:
Total = 6 + 6 + 6.
Key points(Rules) from the question:
1) Opposite sides sums up to 7 [{1,6}, {2,5}, {4,3}]
2) Select Even index dice [ dice2, dice4, dice6 ] & if their top side face have only even number
then how many dots are total in the top face(which are even) of even index dice?
3) Total means summing
4) No of dots on a face = Numeric representation of those dots.
Take dice2
Use rule (1):
5<->2 -> {5 is in front then opposite is 2 which will be on back}
4<->3 -> {4 is in the right then the opposite is 3 which will be on the left}
1<->6 ----> only top face for even index dice = 6 {question said even is always on top so remaining even number is 6}
select 6
take dice4
use rule (1):
5<->2 {2 is on face then opposite 5 will be on back}
4<->3 {4 is on the side then on another side, there will be 3}
1<->6 ----> only top face for even idex dice = 6 {question said only even will be on top & remaining choice for even is 6}
select 6
take dice4
use rule (1):
5<->2
4<->3
1<->6 ----> only top face for even index dice = 6.
select 6 -> same reason as above;
Perform total:
Total = 6 + 6 + 6.
(8)
Bibhas said:
6 months ago
Even numbered dice 1, 2, and 4 now, the top palace should even dots like;
dice 2 top place: 2 or 6
dice 2 top place: 6 [because 2 and 4 are already present]
and dice 4 top place : 2 or 6.
Now compare 2 and 4th dice if the 2nd dice top is 6 then 2's opposite 5 but the 4th dice top can't be 2 because 5 is adjacent so it's top will be 6 also
and if the 2nd dice top is 2 then 5's opposite 6, now 4th top can't be 6 because 5 is adjacent so it will be 2 also;
Now;
total of even numbers dice may be 6+6+6 or 2+6+2 so 18 or 10
So, the answer will be 18.
Now in 4th dice.
dice 2 top place: 2 or 6
dice 2 top place: 6 [because 2 and 4 are already present]
and dice 4 top place : 2 or 6.
Now compare 2 and 4th dice if the 2nd dice top is 6 then 2's opposite 5 but the 4th dice top can't be 2 because 5 is adjacent so it's top will be 6 also
and if the 2nd dice top is 2 then 5's opposite 6, now 4th top can't be 6 because 5 is adjacent so it will be 2 also;
Now;
total of even numbers dice may be 6+6+6 or 2+6+2 so 18 or 10
So, the answer will be 18.
Now in 4th dice.
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