Verbal Reasoning - Dice - Discussion

Consider a dice,opposite faces are always in pairs(1,6)(2,5)(3,4)

->"No need to look at the condition"

1)In 1st ques we want even numbered dice i.e 2,4 and 6th dice top faces with even no.
from fig(2) we can see that 4 and 5 are visible means we have 3 opposite of 4 and 2 opposite of 5.so now we are left with 1 and 6.
now we want 6 at the top(even)so 1 wiil be at the bottom face
so from 2nd dice we got 6

Similarly in 4th dice we can see 2 and 4, means 5 will be opposite of 2 and 3 will opposite of 4 left with 1 and 6
we want 6(even) at the top so 1 wiil be at the bottom face
so from 4th dice we get 6

Similarly in 6th dice we can see 4 and 5, means 3 will be opposite of 4 and 2 will opposite of 5 left with 1 and 6
we want 6(even) at the top so 1 wiil be at the bottom face
so from 6th dice we get 6

Adding 6+6+6=18.

Using above procedure rest of the problems can be solved easily.

Rohit best explanation! keep it up !

Keep in mind that the sum of the numbers of dots on the opposite face is 7.
take 4 dotted face : here from figure the adjacent faces are [5,3,2] and the remaining are {1,3} so opp. to 4 is 3 (4+3=7).

Take 5 dotted face : here from figure the adjacent faces are [4,1] and the remaining are {2,3,6} so opp. to 5 is 2 (5+2=7).

Take 6 dotted face : here from figure the adjacent faces are [3,5] and the remaining are {1,2,4} so opp. to 6 is 1 (6+1=7).

Keep in mind that here even numbers can only be 2,4,and 6.

Now consider (II) : here 4 is there,and opp. to 5 is 2 then only possibility is 6 on top.

Consider (IV): here 2 and 4 is there then only possibility is 6 on top.
Consider (VI): same as (II). so 6 on top.

So adding 6+6+6 = 18 is the answer.

Nicely explained but too long answer I don't think this will come for nata exam.

I think 2 4 6 dice contain 9, 6, 9 dots so answer will be 24 I think once 0 through this.

But by the figures V and VI, 1 is opposite to 4.

Well done Rohit now I understood the question very well. Thanks a lot.

Thanks @Anand.

As explained above all 6, except 5th are having 1 at the bottom. And all should have 6 at the top, but 1st dice is having 6 adjacent to 1.

These are standerd dice and each nearest faces sum is not equal to 7 that's why we taking 6.