Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 2 (Q.No. 26)
26.
Nitin's age was equal to square of some number last year and the following year it would be cube of a number. If again Nitin's age has to be equal to the cube of some number, then for how long he will have to wait?
Answer: Option
Explanation:
Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.
Such numbers are 25 and 27.
Thus, Nitin is now 26 years old. Since the next perfect cube after 27 is 64,
so required time period = (64 - 26) years = 38 years.
Discussion:
2 comments Page 1 of 1.
Dhruvan said:
4 years ago
5^2 = 25 (perfect square),
3^3 = 27 (perfect cube),
So next perfect cube (after 3^3) is 4^3 = 64.
He is 26 years right now and the next to perfect cube is 64 so 64-26 = 38.
3^3 = 27 (perfect cube),
So next perfect cube (after 3^3) is 4^3 = 64.
He is 26 years right now and the next to perfect cube is 64 so 64-26 = 38.
Vishnu Soman said:
6 years ago
Explain it.
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