Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 17)
17.
There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?
Answer: Option
Explanation:
Let x and y be the number of deer and peacocks in the zoo respectively. Then,
x + y = 80 ...(i) and
4x + 2y = 200 or 2x + y = 100 ...(ii)
Solving (i) and (ii), we get) x = 20, y = 60.
Discussion:
13 comments Page 1 of 2.
Arup Das said:
3 years ago
L/2 - H.
= 200/2 - 80.
= 100 - 80,
= 20.
= 200/2 - 80.
= 100 - 80,
= 20.
(1)
Shreyas Singh said:
5 years ago
Heads = 80(total heads)÷2(no. Of animals) = 40,
Legs = 200(total legs)÷2(no.of animals) = 100.
Now, 100 - 40 = 60 peacocks. Becoz total head was 80 n it's logics that less heads more legs n more heads less legs. For this type of questions;
Another way only ÷legs i.e. 200÷2=100 now 100-80( total heads).
= 20 again concept and logic are the same above mentioned. Less leg more heads less heads more legs.
Legs = 200(total legs)÷2(no.of animals) = 100.
Now, 100 - 40 = 60 peacocks. Becoz total head was 80 n it's logics that less heads more legs n more heads less legs. For this type of questions;
Another way only ÷legs i.e. 200÷2=100 now 100-80( total heads).
= 20 again concept and logic are the same above mentioned. Less leg more heads less heads more legs.
Venkat said:
8 years ago
Here total heads =80, legs=200, 60*2=120, 20*4=80, 120+80=200 legs, here 20=deers, 60=peacocks.
Shahrukh Mansuri said:
8 years ago
The Trick is
= total legs - (total heads*reverse legs)/difference of animal legs.
200-(80*4)/2 = 60 Peacock.
= total legs - (total heads*reverse legs)/difference of animal legs.
200-(80*4)/2 = 60 Peacock.
Ramesh Gupta said:
8 years ago
Well, This is very one touch simple trick : (By this trick we will found always two leg animals)
Given : Total Heads = 80, Total Legs =200.
Now,
The Trick is;
Two Leg Animal = (Total Legs - Total Heads)/2.
So,
Two Leg Animal = (200-80)/2 = 60 Peacock.
Given : Total Heads = 80, Total Legs =200.
Now,
The Trick is;
Two Leg Animal = (Total Legs - Total Heads)/2.
So,
Two Leg Animal = (200-80)/2 = 60 Peacock.
(3)
Viki said:
8 years ago
There are x elephant and x man if the number both legs are 100 and number of both head is 50 then how many number elephant and how many numbers of man?
Rahul said:
8 years ago
X+y = 80.
4x+2y = 200.
Then multiple with 4.
4x+4y = 320,
4x+2y = 200,
2y = 120,
Y = 60.
4x+2y = 200.
Then multiple with 4.
4x+4y = 320,
4x+2y = 200,
2y = 120,
Y = 60.
Pooja said:
9 years ago
Simply multiply number of heads by 2.
So, 80 * 2 = 160.
Now subtract this no by the no of heads it's 200 - 160 = 40
Now divide 40 by 2 it's 20.
20 are the number of deer.
So, 80 - 20 = 60 => peacock.
So, 80 * 2 = 160.
Now subtract this no by the no of heads it's 200 - 160 = 40
Now divide 40 by 2 it's 20.
20 are the number of deer.
So, 80 - 20 = 60 => peacock.
Satwinder singh said:
9 years ago
Short method let peacock p and dear 80-p.
2p+4(80-p) = 200.
2p+320-4p = 200.
-2p = -120.
P = 60.
2p+4(80-p) = 200.
2p+320-4p = 200.
-2p = -120.
P = 60.
Satwinder singh said:
9 years ago
Short method let peacock p and dear 80-p.
2p+4(80-p) = 200.
2p+320-4p = 200.
-2p = -120.
P = 60.
2p+4(80-p) = 200.
2p+320-4p = 200.
-2p = -120.
P = 60.
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