Verbal Reasoning - Arithmetic Reasoning - Discussion

Discussion :: Arithmetic Reasoning - Section 1 (Q.No.17)

17. 

There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?

[A]. 20
[B]. 30
[C]. 50
[D]. 60

Answer: Option D

Explanation:

Let x and y be the number of deer and peacocks in the zoo respectively. Then,

x + y = 80 ...(i) and

4x + 2y = 200 or 2x + y = 100 ...(ii)

Solving (i) and (ii), we get) x = 20, y = 60.


Raju said: (Feb 5, 2013)  
Can anyone tell me how to solve above question through allegation method?

Engr Tanoli said: (Jul 25, 2013)  
Total Numbers of heads = 80(consist on peacock's and deer heads).

Let X be the dear heads, and y be the peacock heads.

Deer heads +peacock heads = Total heads.

X+Y = 80 ------- 1.

Each deer 4 legs and each peacock 2 legs, now total given legs 200.

Deer legs+peacock legs = total legs.

4X+2Y = 200.
2(2X+Y) = 200.
2X+Y=100 ------- 2.

Solving (i) and (ii), we get x = 20, y = 60.

Saravanan said: (Jan 7, 2014)  
Let x as deer and y as Peacock.
Now,

x+y=80--(i).
4x+2y=200--(ii).

Solve (i) and (ii) by multiplying (i) by 4.
y = 60 .

Peacock = 60.

Satwinder Singh said: (Mar 19, 2016)  
Short method let peacock p and dear 80-p.
2p+4(80-p) = 200.
2p+320-4p = 200.
-2p = -120.
P = 60.

Satwinder Singh said: (Mar 19, 2016)  
Short method let peacock p and dear 80-p.
2p+4(80-p) = 200.
2p+320-4p = 200.
-2p = -120.
P = 60.

Pooja said: (May 3, 2016)  
Simply multiply number of heads by 2.
So, 80 * 2 = 160.

Now subtract this no by the no of heads it's 200 - 160 = 40
Now divide 40 by 2 it's 20.
20 are the number of deer.

So, 80 - 20 = 60 => peacock.

Rahul said: (Jun 2, 2017)  
X+y = 80.
4x+2y = 200.
Then multiple with 4.
4x+4y = 320,
4x+2y = 200,
2y = 120,
Y = 60.

Viki said: (Jul 11, 2017)  
There are x elephant and x man if the number both legs are 100 and number of both head is 50 then how many number elephant and how many numbers of man?

Ramesh Gupta said: (Aug 8, 2017)  
Well, This is very one touch simple trick : (By this trick we will found always two leg animals)

Given : Total Heads = 80, Total Legs =200.
Now,

The Trick is;
Two Leg Animal = (Total Legs - Total Heads)/2.
So,

Two Leg Animal = (200-80)/2 = 60 Peacock.

Shahrukh Mansuri said: (Nov 1, 2017)  
The Trick is
= total legs - (total heads*reverse legs)/difference of animal legs.

200-(80*4)/2 = 60 Peacock.

Venkat said: (Feb 10, 2018)  
Here total heads =80, legs=200, 60*2=120, 20*4=80, 120+80=200 legs, here 20=deers, 60=peacocks.

Shreyas Singh said: (Feb 6, 2021)  
Heads = 80(total heads)÷2(no. Of animals) = 40,
Legs = 200(total legs)÷2(no.of animals) = 100.
Now, 100 - 40 = 60 peacocks. Becoz total head was 80 n it's logics that less heads more legs n more heads less legs. For this type of questions;

Another way only ÷legs i.e. 200÷2=100 now 100-80( total heads).

= 20 again concept and logic are the same above mentioned. Less leg more heads less heads more legs.

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