# Verbal Reasoning - Arithmetic Reasoning - Discussion

### Discussion :: Arithmetic Reasoning - Section 1 (Q.No.17)

17.

There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?

 [A]. 20 [B]. 30 [C]. 50 [D]. 60

Explanation:

Let x and y be the number of deer and peacocks in the zoo respectively. Then,

x + y = 80 ...(i) and

4x + 2y = 200 or 2x + y = 100 ...(ii)

Solving (i) and (ii), we get) x = 20, y = 60.

 Raju said: (Feb 5, 2013) Can anyone tell me how to solve above question through allegation method?

 Engr Tanoli said: (Jul 25, 2013) Total Numbers of heads = 80(consist on peacock's and deer heads). Let X be the dear heads, and y be the peacock heads. Deer heads +peacock heads = Total heads. X+Y = 80 ------- 1. Each deer 4 legs and each peacock 2 legs, now total given legs 200. Deer legs+peacock legs = total legs. 4X+2Y = 200. 2(2X+Y) = 200. 2X+Y=100 ------- 2. Solving (i) and (ii), we get x = 20, y = 60.

 Saravanan said: (Jan 7, 2014) Let x as deer and y as Peacock. Now, x+y=80--(i). 4x+2y=200--(ii). Solve (i) and (ii) by multiplying (i) by 4. y = 60 . Peacock = 60.

 Satwinder Singh said: (Mar 19, 2016) Short method let peacock p and dear 80-p. 2p+4(80-p) = 200. 2p+320-4p = 200. -2p = -120. P = 60.

 Satwinder Singh said: (Mar 19, 2016) Short method let peacock p and dear 80-p. 2p+4(80-p) = 200. 2p+320-4p = 200. -2p = -120. P = 60.

 Pooja said: (May 3, 2016) Simply multiply number of heads by 2. So, 80 * 2 = 160. Now subtract this no by the no of heads it's 200 - 160 = 40 Now divide 40 by 2 it's 20. 20 are the number of deer. So, 80 - 20 = 60 => peacock.

 Rahul said: (Jun 2, 2017) X+y = 80. 4x+2y = 200. Then multiple with 4. 4x+4y = 320, 4x+2y = 200, 2y = 120, Y = 60.

 Viki said: (Jul 11, 2017) There are x elephant and x man if the number both legs are 100 and number of both head is 50 then how many number elephant and how many numbers of man?

 Ramesh Gupta said: (Aug 8, 2017) Well, This is very one touch simple trick : (By this trick we will found always two leg animals) Given : Total Heads = 80, Total Legs =200. Now, The Trick is; Two Leg Animal = (Total Legs - Total Heads)/2. So, Two Leg Animal = (200-80)/2 = 60 Peacock.

 Shahrukh Mansuri said: (Nov 1, 2017) The Trick is = total legs - (total heads*reverse legs)/difference of animal legs. 200-(80*4)/2 = 60 Peacock.

 Venkat said: (Feb 10, 2018) Here total heads =80, legs=200, 60*2=120, 20*4=80, 120+80=200 legs, here 20=deers, 60=peacocks.

 Shreyas Singh said: (Feb 6, 2021) Heads = 80(total heads)÷2(no. Of animals) = 40, Legs = 200(total legs)÷2(no.of animals) = 100. Now, 100 - 40 = 60 peacocks. Becoz total head was 80 n it's logics that less heads more legs n more heads less legs. For this type of questions; Another way only ÷legs i.e. 200÷2=100 now 100-80( total heads). = 20 again concept and logic are the same above mentioned. Less leg more heads less heads more legs.