Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 17)
17.
There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?
Answer: Option
Explanation:
Let x and y be the number of deer and peacocks in the zoo respectively. Then,
x + y = 80 ...(i) and
4x + 2y = 200 or 2x + y = 100 ...(ii)
Solving (i) and (ii), we get) x = 20, y = 60.
Discussion:
13 comments Page 2 of 2.
Saravanan said:
1 decade ago
Let x as deer and y as Peacock.
Now,
x+y=80--(i).
4x+2y=200--(ii).
Solve (i) and (ii) by multiplying (i) by 4.
y = 60 .
Peacock = 60.
Now,
x+y=80--(i).
4x+2y=200--(ii).
Solve (i) and (ii) by multiplying (i) by 4.
y = 60 .
Peacock = 60.
Engr tanoli said:
1 decade ago
Total Numbers of heads = 80(consist on peacock's and deer heads).
Let X be the dear heads, and y be the peacock heads.
Deer heads +peacock heads = Total heads.
X+Y = 80 ------- 1.
Each deer 4 legs and each peacock 2 legs, now total given legs 200.
Deer legs+peacock legs = total legs.
4X+2Y = 200.
2(2X+Y) = 200.
2X+Y=100 ------- 2.
Solving (i) and (ii), we get x = 20, y = 60.
Let X be the dear heads, and y be the peacock heads.
Deer heads +peacock heads = Total heads.
X+Y = 80 ------- 1.
Each deer 4 legs and each peacock 2 legs, now total given legs 200.
Deer legs+peacock legs = total legs.
4X+2Y = 200.
2(2X+Y) = 200.
2X+Y=100 ------- 2.
Solving (i) and (ii), we get x = 20, y = 60.
(1)
Raju said:
1 decade ago
Can anyone tell me how to solve above question through allegation method?
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