Verbal Reasoning - Arithmetic Reasoning - Discussion

Let, A to B fare as X and A to C as Y

(2x + 3y = 77)X 3 ---------------(1 line)
(3x + 2y = 73)X 2 ---------------(2 line)
now, after multiplications, we get

6x + 9y = 231---------------(1 line)
6x + 4y = 146---------------(2 line)

now, after change the signs and solve the equation, we will get

6x + 9y = 231
-6x - 4y =-146
----------------
ox + 5y = 85

OR,5y = 85

Y= 85/5
OR, Y= 17
NOW, put the value of y in any line, for Eg. in first line, as under:-

2x+3y=77------(1 line)
2x+3(17)=77
2x+51=77
OR, 2x=77-51
2x=26
x=26/2
x=13
SO,
13 and 17 is the answer

Vijay why did you first multiply by 3 and then by 2 why not the reverse... How would you manage the negative output when you multiply first line by 2 and second line by 3

i.e 4x + 6y
9x + 6x
-------------
Minus = 5x ?

Don't know if I made sense with my question.

Vijay method is correct.

It is wrong antony. In options 17 and 13 is also there. So your method is wrong.

New method

3 tickets A to B
2 tickets A to c
that's 77/5 = 15.4

3 tickets A to B
2 tickets A to C
that's 73/5 = 14.6

so 15.4+14.6 = 30
Ans: 13 + 17 = 30 --- (B)

2x + 3y = 77 multiply this line with 3 so it becomes
6x + 9y = 231-----------(i)

3x + 2y = 73 multiply this line with 2 so it becomes
6x + 4y = 146 -------------(ii)

now solve both the equestion (i) and (ii)
6x + 9y = 231
6x + 4y = 146
----------------
ox + 5y = 85

y = 85/5 = 17

in the same way do for X ..

I cant get this, please explain (1) and (ii).

I am truly lost, please help. Where does (i) and (ii) fit in?

I cant get this, please explain.