Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 2)
2.
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Answer: Option
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Discussion:
49 comments Page 4 of 5.
Pvk said:
1 decade ago
Antony method super and correct substitute the x, y value in 1, 2 equation. Only 13, 17 satisfying.
Reghu R said:
1 decade ago
2x+3y = 77 --------- i.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
3x+2y = 73 --------- ii.
---------
i*2 => 4x+6y = 154.
ii*3 => 9x+6y = 219.
5x=65; x=65/5; x=13; 26+3y=77; 3y=77-26; 3y=51; y=17.
Answer = Rs.13 and Rs.17.
Aneri Desai said:
1 decade ago
s2b(2) & s2a(3) = 77.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
s2b(3) & s2a(2) = 73.
s2b=x=? & s2a=y=?
4x+6y = 154.
9x+6y = 219.
-5x = -65.
x = 13.
y = 17.
Sajid khan said:
1 decade ago
2x + 3y = 77.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
3x + 2y = 73.
Solution :
2x + 3y = 77 (i)multiplying by 3.
6x + 9y = 231.
3x + 2y = 73 (ii)multiplying by 2.
6x + 4y = 146.
Now subtract its,
6x + 9y = 231.
6x - 4y = -146.
0x + 5y = 85.
5y = 85.
y = 85/5.
Ans y = 17.
Now put y value on the equation (i).
6x + 9(17) = 231.
6x + 153 = 231.
6x + 153 - 231 = 0.
6x - 78 = 0.
x = 78/6.
x = 13.
Solution set is { 13 , 17 }.
Dazedandconfused said:
1 decade ago
For some reason, this seems complicated to me. What is the purpose of these tests?
M.Haseeb Sahal Shah said:
1 decade ago
2x+3y = 77.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).
3x+2y = 73.
Put x value,
3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.
x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.
B is answer 13, 17.
2x = 77 -3y.
x = 77 - 3y /2 ... (1).
3x+2y = 73.
Put x value,
3(77 - 3y /2)+ 2y = 73.
3(77 - 3y)= 2(73-2y).
231-9y = 146-4y.
231-146 = -4y+9y.
85 = 5y.
85/5 =y.
17 = y.
x = 77 - 3y /2 ... (1).
x = 77 - 3(17) /2.
x = 77 - 51 /2.
x = 26/2.
x = 13.
B is answer 13, 17.
Jitendra said:
1 decade ago
New method by @Antony is really good and a short-cut way to find the solution.
Ramkumar said:
1 decade ago
Its very simple.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
It is a optional based solution .
There forms :
2x+3y = 77.
3x+2y = 73 (then we find x and y).
Simply check with A B C D options.
Now option B is: 13, 17 is satisfies the above equations.
Anam charan patra said:
1 decade ago
Please explain why multiply 3 series (i) and 2 multiply series (ii)?
Madhu said:
1 decade ago
@Vijay
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
You are method is so good. easy way to understand..in Vijay method if any x,y coefficient should made equal to the values. Because we find x,y values..thats why he multiple 3 with first equation and 2 with second equation.
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