Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
81 comments Page 3 of 9.
Bin Yamin said:
8 years ago
Let total number of girls in the institute=x.
Total number of boys=y.
Now,
Girls participate 1/5 of x and boys participate 1/8 of y
Which becomes
x/5+y/8.
8x+5y/40 is correct answer.
which is not found in the given answer.
Therefore inadequate.
Total number of boys=y.
Now,
Girls participate 1/5 of x and boys participate 1/8 of y
Which becomes
x/5+y/8.
8x+5y/40 is correct answer.
which is not found in the given answer.
Therefore inadequate.
Udit said:
8 years ago
According to me, it is 13/40 as it has asked us the total no of boys and girls participating in the fete.
So we can solve as:
1/5 girls + 1/8 of boys = total no of students participated in that fete.
Adding we would get 13/40 or OPTION B.
So we can solve as:
1/5 girls + 1/8 of boys = total no of students participated in that fete.
Adding we would get 13/40 or OPTION B.
Gayathri said:
6 years ago
The ratio of girls is 1/5th not the total people for suppose if there r 30 girls then no.of girls participated is 6 and if no.of boys r 24 then 1/8th is 3 nd total participated is 9 and ratio would be 9/54 which is 1/6 so data is inadequate.
(4)
MALAY PANDEY said:
9 years ago
According to me, it is 13/40 as it has asked us the total no of boys and girls participating in the fete.
So we can solve as.
1/5 girls + 1/8 of boys = total no of students participated in that fete.
Adding we would get 13/40 or OPTION B.
So we can solve as.
1/5 girls + 1/8 of boys = total no of students participated in that fete.
Adding we would get 13/40 or OPTION B.
SAGILI RAMANAREDDY said:
1 decade ago
Suggest me if this logic is wrong:
If X is the boys and Y is girls ,and also given 1/5 of boys and 1/8 of girls. Here but not given total number of students participated in that fete
(1/5)x+(1/8)y=? So I think answer is "C".
If X is the boys and Y is girls ,and also given 1/5 of boys and 1/8 of girls. Here but not given total number of students participated in that fete
(1/5)x+(1/8)y=? So I think answer is "C".
Gangadhri said:
9 years ago
The correct answer is 2/12 because the total no of girls = 5, participated girls = 1 and total no of boys = 8 participated boys = 1.
So total no of students = 13 particepated students= 2.
Then by the fraction it is = 2/13.
So total no of students = 13 particepated students= 2.
Then by the fraction it is = 2/13.
Kiran Kumar said:
7 years ago
Here the Hidden number is = Total number of Students.
You have to assume a number.
So, we multiply denominators and that should be the total number of students.
(1/5)*40 = 8.
(1/8)*40 = 5,
8+5 = 13
Answer = 13/40.
You have to assume a number.
So, we multiply denominators and that should be the total number of students.
(1/5)*40 = 8.
(1/8)*40 = 5,
8+5 = 13
Answer = 13/40.
(10)
Abhishek said:
1 decade ago
Suggest me if this logic is wrong.
Let there are 5 girls and 8 boys.
Then total no students=13
No of girls participated =1
No of boys participated =1.
So, Total participation =2.
Thus, ratio=2/13.
Let there are 5 girls and 8 boys.
Then total no students=13
No of girls participated =1
No of boys participated =1.
So, Total participation =2.
Thus, ratio=2/13.
Ashwin said:
1 decade ago
Take total boys as 10 and total girls as 16 for easier calculation. So total strength is 26.
Calculate ratio of boys and girls participated and add them. And find fraction to 26.
You will get 2/13.
Calculate ratio of boys and girls participated and add them. And find fraction to 26.
You will get 2/13.
Manika said:
1 decade ago
According to my opinion it should be 13/40, because
1/5+1/8 = 13/40,
because the question only ask about the What fraction of the total number of students took part in the fete?.
1/5+1/8 = 13/40,
because the question only ask about the What fraction of the total number of students took part in the fete?.
(1)
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