Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
82 comments Page 2 of 9.
Rajiv said:
1 decade ago
Manika, Harshita the Answer is "Data Inadequate", because for answer to be correct, it has to be true for all values. But here it changes with values. Option A. Total girls 5, Total Boys 8, answer is 2/13, but Option B, 5 girls and 16 boys, it comes 3/21 which is equivalent to 2/14 (completely diff. from 2/13 derived earlier.
Jaydip said:
7 years ago
Say for Example total student is X. We have to assume as this number is not given;
Now, Boys participated = X/8,
Girls Participated = X/5,
Total Number of student participated = X/8 +X/5 = 13X/40,
Here if you dont know X you wil never be able to know value fo total number of student participated.
Thus data inadequate.
Now, Boys participated = X/8,
Girls Participated = X/5,
Total Number of student participated = X/8 +X/5 = 13X/40,
Here if you dont know X you wil never be able to know value fo total number of student participated.
Thus data inadequate.
(2)
Nalinikanta said:
9 years ago
According to the question, we are not informed regarding the total no of students.
So, let total no of students = x.
No of girls participated = x/5
No of boys participated = x/6
So, total no of students participated = 13x/40, then a fraction of the original number of students obtained = 13x/40 * 1/x = 13/40.
So, let total no of students = x.
No of girls participated = x/5
No of boys participated = x/6
So, total no of students participated = 13x/40, then a fraction of the original number of students obtained = 13x/40 * 1/x = 13/40.
Udas Bugti said:
9 years ago
According to me answer is :
Girls participated = 1/5.
Boys participated = 1/8.
It's very simple, it just asking about the total num of participated student,but not 4 total students.
So, 1/5 + 1/8 = 13/40.
The correct answer is 13/40.
If they asked about total students then the correct answer is inadequate.
Girls participated = 1/5.
Boys participated = 1/8.
It's very simple, it just asking about the total num of participated student,but not 4 total students.
So, 1/5 + 1/8 = 13/40.
The correct answer is 13/40.
If they asked about total students then the correct answer is inadequate.
Jim said:
1 decade ago
LCM method cannot be used here. The fractions are given for different genders. So LCM cannot be taken.
And Sneha, percentages can never be added.
Suppose they had given 4/5 of girls and 7/8 of boys participated. Would you add 80% and 87.5% and say 167.5% of the students attended? PERCENTAGES CANNOT BE ADDED.
And Sneha, percentages can never be added.
Suppose they had given 4/5 of girls and 7/8 of boys participated. Would you add 80% and 87.5% and say 167.5% of the students attended? PERCENTAGES CANNOT BE ADDED.
Rawat said:
1 decade ago
Ans is "Data inadequate".
Suppose ther are 18 students (10 girls, 8 boys).
1/5 of 10=2 (girls).
1/8 of 8=1 (boy).
Total participation=2+1=3.
Total students=10+8=18.
Answer = 3/18 = 1/6.
Answer cannot be determined until we have the "Ratio of girls to boys".
Suppose ther are 18 students (10 girls, 8 boys).
1/5 of 10=2 (girls).
1/8 of 8=1 (boy).
Total participation=2+1=3.
Total students=10+8=18.
Answer = 3/18 = 1/6.
Answer cannot be determined until we have the "Ratio of girls to boys".
(1)
John said:
10 years ago
All of the above do not address the fact that the boys and girls of the "institute" may include non "students" or adults if "boy" and "girls" is meant to distinguish from non-juvenile students. Sloppy questions can often lead to ambiguities and so many answers.
Lekden said:
6 months ago
The answer is C. Data inadequate.
Although we can fine the fraction of the number of the student who took part in the fete as 2/13 but we cannot fine the exact number of students who took part in the fete since the total number of students is not given.
Although we can fine the fraction of the number of the student who took part in the fete as 2/13 but we cannot fine the exact number of students who took part in the fete since the total number of students is not given.
(3)
Navdeep said:
10 years ago
I agree with option B.
Because here the no. of girls are participated is 1/5.
And no. of boys are participated is 1/8.
And here ask what is the fraction of students that are participated.
So, 1/5+1/8 is equal to 13/40.
By taking L.C.M. of 1/5+1/8.
Because here the no. of girls are participated is 1/5.
And no. of boys are participated is 1/8.
And here ask what is the fraction of students that are participated.
So, 1/5+1/8 is equal to 13/40.
By taking L.C.M. of 1/5+1/8.
Dhananjay Singh said:
1 decade ago
@Sneha.
I love the way you added %age of boys and %age of girls to find out the total %age of participation. As per your logic if total boys and total girls participate the fete then total participation will turn to 200% just a minor increase of 100%.
I love the way you added %age of boys and %age of girls to find out the total %age of participation. As per your logic if total boys and total girls participate the fete then total participation will turn to 200% just a minor increase of 100%.
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