Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 19)
19.
A motorist knows four different routes from Bristol to Birmingham. From Birmingham to Sheffield he knows three different routes and from Sheffield to Carlisle he knows two different routes. How many routes does he know from Bristol to Carlisle ?
Answer: Option
Explanation:
Total number of routes from Bristol to Carlisle = (4 x 3 x 2) = 24.
Discussion:
18 comments Page 1 of 2.
GARY said:
5 years ago
Agree, @Mausam Kumar.
It's because.
1. a1b1c1.
2. a1b1c2.
3. a1b2c1.
4. a1b2c2.
5. a1b3c1.
6. a1b3c2.
It's because.
1. a1b1c1.
2. a1b1c2.
3. a1b2c1.
4. a1b2c2.
5. a1b3c1.
6. a1b3c2.
Rishav Singla said:
5 years ago
Why we have to multiply it?
Bhaskar said:
6 years ago
Total known route 4.
So, 3 * 2 * 4 = 24.
So, 3 * 2 * 4 = 24.
Siyad said:
8 years ago
Well said @Mausam Kumar.
Abinaya said:
8 years ago
Your method is correct. Thankyou @G03.
Elly said:
9 years ago
Not understand that why multiplying it?
Please clarify this.
Please clarify this.
Amr said:
9 years ago
I think 12 is the right answer 4 + 3 + 2 + 3 (the main routes) = 12.
* If we will take into consideration that each route has 2 ways so the answer will be 24.
* If we will take into consideration that each route has 2 ways so the answer will be 24.
MAUSAM KUMAR said:
9 years ago
Here routes should we multiplied.
Here point A to B lets assume 4 routes a1, a2, a3, a4 then from point B to C, 3 routes b1, b2 and b3 and from points C to D, 2 routes c1 and c2.
There will be total 24 routes as 4 * 3 * 2 = 24. Let's see in explanation numbers of routes.
1. a1b1c1.
2. a1b1c2.
3. a1b2c1.
4. a1b2c2.
5. a1b3c1.
6. a1b3c2.
Same Six ways for a2, a3 and a4. So, totally 24 ways.
Here point A to B lets assume 4 routes a1, a2, a3, a4 then from point B to C, 3 routes b1, b2 and b3 and from points C to D, 2 routes c1 and c2.
There will be total 24 routes as 4 * 3 * 2 = 24. Let's see in explanation numbers of routes.
1. a1b1c1.
2. a1b1c2.
3. a1b2c1.
4. a1b2c2.
5. a1b3c1.
6. a1b3c2.
Same Six ways for a2, a3 and a4. So, totally 24 ways.
(5)
Namrataa said:
9 years ago
Why we have to multiple the numbers?
Sam said:
10 years ago
Why we multiplied the numbers not do addition?
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