Online Aptitude Test  Aptitude Test 1
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 Total number of questions: 20.
 Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
Required number = H.C.F. of (91  43), (183  91) and (183  43)
= H.C.F. of 48, 92 and 140 = 4.
L.C.M. of 8, 16, 40 and 80 = 80.
7  =  70  ;  13  =  65  ;  31  =  62 
8  80  16  80  40  80 
Since,  70  >  65  >  63  >  62  , so  7  >  13  >  63  >  31 
80  80  80  80  8  16  80  40 
So,  7  is the largest. 
8 
.009  = .01 
? 
Let  .009  = .01; Then x =  .009  =  .9  = .9 
x  .01  1 
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 2^{2} x 3^{2} x 7^{2} x 11^{2} = 213444
If x =  3 + 1  and y =  3  1  , then the value of (x^{2} + y^{2}) is: 
3  1  3 + 1 
x =  (3 + 1)  x  (3 + 1)  =  (3 + 1)^{2}  =  3 + 1 + 23  = 2 + 3. 
(3  1)  (3 + 1)  (3  1)  2 
y =  (3  1)  x  (3  1)  =  (3  1)^{2}  =  3 + 1  23  = 2  3. 
(3 + 1)  (3  1)  (3  1)  2 
x^{2} + y^{2} = (2 + 3)^{2} + (2  3)^{2}
= 2(4 + 3)
= 14
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
What is Arun's present age?  
I.  Five years ago, Arun's age was double that of his son's age at that time. 
II.  Present ages of Arun and his son are in the ratio of 11 : 6 respectively. 
III.  Five years hence, the respective ratio of Arun's age and his son's age will become 12 : 7. 
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
I. 5 years ago, Arun's age = 2 x His son's age.
III. 5 years hence,  Arun's Age  =  12 
Son's age  7 
Clearly, any two of the above will give Arun's present age.
Correct answer is (D).
20% of a = b  20  a = b. 
100 
b% of 20 =  b  x 20  =  20  a x  1  x 20  =  4  a = 4% of a.  
100  100  100  100 
x% of y =  x  x y  =  y  x x  = y% of x  
100  100 
A = B.
Let the required number of working hours per day be x.
More pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
Pumps  4  :  3  :: 8 : x  
Days  1  :  2 
4 x 1 x x = 3 x 2 x 8
x =  (3 x 2 x 8) 
(4) 
x = 12.
Let the slower pipe alone fill the tank in x minutes.
Then, faster pipe will fill it in  x  minutes. 
3 
1  +  3  =  1  
x  x  36 
4  =  1  
x  36 
x = 144 min.
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15  x) km/hr.
30  +  30  = 4  1  
(15 + x)  (15  x)  2 
900  =  9  
225  x^{2}  2 
9x^{2} = 225
x^{2} = 25
x = 5 km/hr.
Video Explanation: https://youtu.be/lMFnNB3YQOo
Principal = Rs.  100 x 5400  = Rs. 15000.  
12 x 3 
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % =  0.59x  x 100  %  = 30% (approx.)  
2x 
To earn Rs.  50  , investment = Rs. 64. 
3 
To earn Rs. 1500, investment = Rs.  64 x  3  x 1500  = Rs. 5760.  
50 
S.P.  = P.W. of Rs. 2200 due 1 year hence  


= Rs. 2000. 
Gain = Rs. (2000  1950) = Rs. 50.
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.