Non Verbal Reasoning - Classification - Discussion

Discussion :: Classification - Section 1 (Q.No.20)

In each problem, out of the five figures marked (1), (2), (3), (4) and (5), four are similar in a certain manner. However, one figure is not like the other four. Choose the figure which is different from the rest.


Choose the figure which is different from the rest.

   (1)     (2)     (3)     (4)     (5)

[A]. 1
[B]. 2
[C]. 3
[D]. 4
[E]. 5

Answer: Option C


No answer description available for this question.

Kirthi Kumar said: (Dec 21, 2010)  
Hi I think answer is 3 because except 3rd all the inner circles have even number of stripes

Arun said: (Feb 3, 2011)  
2nd and 4th has four loops i.e even number.
And in case of 1st and 5th has 8 & 6 loops
which are of even set.
but in case of 3rd which has got only 7loops
which is odd.

Ravi Kiran said: (Feb 13, 2011)  
Yes 3rd is the correct answer because it has odd number.

Amit said: (Feb 22, 2011)  
From my point of view 3rd because draw the line from the center of circle same no. of leaves are there on both sides in 3 leaves are not there in equal strength.

Ashish said: (Feb 24, 2011)  
They have symmetry among leaves except 3.

Guru said: (Feb 25, 2011)  
1) 7 prime no and others are not...
2) 7 odd others are even...
3) when u c all the figures 1 st ans comes in ur mind is C

Vijaya said: (Mar 2, 2011)  
C is the correct answer because all are having even number leaves but C has 7 leaves that is odd number.

Jayshil said: (Mar 23, 2011)  
3 is incomplete and others are complete in their design.

Jay said: (Apr 14, 2011)  
I think 3rd right because in rest of figs we'll have proper symmetrical figure after cutting by centre line.

Deepali said: (Jul 8, 2011)  
Fig 3 is not symmetrical.

Sawan said: (Sep 12, 2011)  
All contain even number of arc while third contain odd arc.

Rohit Dash said: (Oct 29, 2011)  
Because all other contains symmetrical stripes, i.e. the stripes can be viwed as two equal halves.

Rupa said: (Nov 18, 2011)  
All other figures have a symmetric pattern.

Ps Karthikeyan said: (Sep 17, 2012)  
All fig expect (3) has even no of leaves.

Mary said: (Mar 18, 2013)  
It's obvious to the eye that there is no regular pattern (symmetry).

Anoop A said: (Jul 11, 2013)  
All others can be divided into two symmetrical segments.

Tarun Sikdar said: (Nov 19, 2013)  
Only figure 3 has odd number of elements.

Rahul said: (Dec 14, 2013)  
All figures except 3 have even number of stripes.

Spider said: (Jan 13, 2014)  
All figures have even number of wings except 3.

A.G said: (Jan 30, 2014)  
Two reasons, all of the figures have an even number of loops other than c and all of the loops are have a match on the other side other than c which has 7 sides so there is not a match for one side.

Aparna said: (Mar 29, 2014)  
I think it is the 3 because all the others look like they have all the petals.

Srikanya said: (Mar 31, 2014)  
Here except in the fig C., all the ovals have opposite ovals in the circle but for C, there is no oval's oppositely placed.

M.Harika said: (May 4, 2014)  
Yes, the correct answer is third one as it has odd number of loops.

Lobsang said: (May 14, 2014)  
Yes! it is 3 as since all others diagrams have got the even no of leaves except 3. That's why 3 is the correct answer.

Aryan Kanojia said: (Oct 6, 2014)  
I think because the figure is almost complete but it is lacking by one loop at its extreme right.

Skaterboy ( S.B ) said: (Nov 9, 2014)  
If your dumb and your taking this test here's the simple version.

Its 3 because its the only 1 where there's an odd (not even) amount of flower petals (or what ever they were).

Subhadra said: (Jul 21, 2015)  
3rd one is correct because it has odd number of loops.

Manish said: (Sep 8, 2015)  
In all other figures, are in pairs in radius but option 3rd is not in one is not pair.

Utkarsh said: (Oct 7, 2015)  
Others are similar about an axis.

Bhargavi said: (Nov 30, 2015)  
I want to say that except 3 1, 2, 4, 5 having opposite rings to it but in 3rd picture one ring is not having exact opposite pair.

All Figures Except (3) Has Odd Number Of Figure. said: (Jan 18, 2016)  
All figures except (3) has odd number of figure.

Jeslet Joy Pala said: (Jan 21, 2016)  
All pictures other than 3 is even number.

Dharmaprakash said: (Apr 15, 2016)  
Except 3 all the other figures are symmetric.

Aakash said: (Apr 25, 2016)  
The 3rd option is the only one which is not symmetric as the other 4 figures.

Arsenalfc said: (May 9, 2016)  
Another logic : 3 is an odd number.

Lovi said: (Jun 17, 2016)  
Because shape three has an odd number of stripes.

Vaishnavi said: (Jul 21, 2016)  
Aside from 3 having odd number of petals it is the only option in which there are is 1 petal missing in the diagonal.

Vijayakanth said: (Jul 28, 2016)  
I think answer is 4th figure that one differs from rest of all.

Laxman Bk said: (Aug 11, 2016)  
I think the answer is 3, that's not one loop which radius.

Shraddha Jain said: (Sep 20, 2016)  
3rd is correct because the structure is incomplete.

Sai said: (Oct 3, 2016)  
I think you are wrong @Akhil Balakrishnan.

Suresh S said: (Nov 18, 2016)  
Yes, 3rd figure is the correct answer. It contains the odd number.

Papa said: (Nov 28, 2016)  
All of the petals or leaves are equal but three isn't.

Arpit said: (Dec 26, 2016)  
Each figure can be a mirror image if we draw a line except the third figure.

Shobhit Prakash said: (Jan 9, 2017)  
Mirror image of the other figure except 3 is same.

Chaitanya J.Bharat said: (Jan 13, 2017)  
In all the other fig. Petals are distributed equally in opposite sides except in fig 3.

Suraj Soni said: (Feb 14, 2017)  
Yes, 3 is correct answer because it has odd no of spaces.

Subham said: (May 27, 2017)  
Because it's unsymmetrical.

Shagun said: (Jun 5, 2017)  
I think that 3 could be the answer because it doesn't have one oval.

Subhasis Parija said: (Jun 7, 2017)  
I think it is 3 because all the figure having an even number of leaves inside the circules. Except 3rd circle (odd number).

Roonak Khandelwal said: (Jun 10, 2017)  
All except 3 fig are in even strips.

Rafael Ventura said: (Jun 11, 2017)  
Here, all are symmetric.

Vaibhav Yadav said: (Jun 25, 2017)  
Hi, I think it's the 3rd one because the no in all is even and other can also be taken as somewhere in all the circle the distance is same.

Anirudh said: (Jul 1, 2017)  
A line cutting opposite petals midway, will produce symmetrical parts in all figures, except 3.

Subashini said: (Jul 1, 2017)  
Except fig 3 all others contain even no of strips.

Akshay Joshi said: (Aug 18, 2017)  
The 3rd option is correct because the odd number of strips present in it.

Arunava Mondal said: (Sep 2, 2017)  
I think the answer is 3 because, all except 3 fig are in even strips.

Antigana said: (Sep 3, 2017)  
All other figures have each lines projected in one poit to other poit of its figure. Except Figure 3 does not express such feature.

Ronaldo said: (Oct 28, 2017)  
Except 3 all loops are even.

Salwi said: (Dec 15, 2017)  
C is the correct answer because it has odd Leaf and other have even leaf.

Winne said: (Dec 22, 2017)  
All of them have opposite ovals but number three is missing.

Hardik said: (Jan 10, 2018)  
But in my opinion 1, 3, 5 figure one one loop is decrease but in 2, 4 figure same loop is there no loop is decreased so I think answer is 4.

Anil said: (Mar 15, 2018)  
C is the odd number.

Sagar said: (Jul 18, 2018)  
Because it is an Even number wheel.

Neetis said: (Sep 25, 2018)  
Each and every figure has more than 1 line of symmetry. Figure C has only one. So, it will be the answer.

Dev said: (Oct 27, 2018)  
In other figures, there is even number but in figure 3 the circle comprise odd number loops (7).

Chandru said: (Jan 30, 2019)  
Except C (3) all are having an even number of wheels in option 3 only it has odd 7 number of wheels.

Ronit said: (Feb 1, 2019)  
Number 3 is correct because it is odd and all other figures are even.

Dar Musadiq said: (Feb 6, 2019)  
All others are radially symmetric except 3.

Juan said: (Mar 24, 2019)  
All of them have a pair number of stripes and the tird has an unpair number of stripes.

Nihal said: (Apr 22, 2019)  
I think all of them have a symmetrical line except 3.

Sachin Kumar said: (Apr 24, 2019)  
Here, Every figure has even no of loop except fig 3.

Manish said: (Jun 21, 2019)  
I think in all the figure except 3, all the loops are completely mirrored. But in 3 it doesn't complete the loop of another side.

Manju Mam said: (Jul 23, 2019)  
The answer is 3 as each of the leaves in the circle have a corresponding leaf at the opposite side and each figure has an even number of leaves except for figure 3.

Saipranav said: (Oct 15, 2019)  
In 3 it has an odd number of leaves in others there are even number of leaves.

Ohm Nabhya said: (Oct 20, 2019)  
The answer is (C) 3 because the number of lines in the figures except (C) has even numbers.

Mohan Singh said: (Dec 6, 2019)  
They have symmetry among leaves except 3.

Ravi Kumar said: (Dec 24, 2019)  
Except 3, all other are symmetric.

Akshay Anand said: (Feb 27, 2020)  
Petals are in even no. In each circle except 3rd fig.

Eric Chin said: (May 5, 2020)  
Answer C is the correct one, because it is the only figure which has a missing petal.

Akshay said: (Jul 13, 2020)  
Yes. Option 3 is correct because all the circles has even number of petals except third one.

Zainab said: (Jul 15, 2020)  
I think the answer is 3 because it is not symmetrical, while the others are.

Piyush Mandal said: (Aug 29, 2020)  
3 is answer because others have more than 2 line of symmetry.

And this only has 1 line of symmetry.

Hafsa Mughal said: (Sep 4, 2020)  
Because C has an odd number of stripes.

Kriti Jindal said: (Oct 26, 2020)  
The rest of the figures have even number of petals, but number 3 has odd number (7) of petals.

Ronak said: (Apr 26, 2021)  
(3) has no horizontal line of symmetry while others have horizontal line of symmetry.

Veerendra Nadh said: (Jun 5, 2021)  
All circles have an even number of leaves except option 3. So, it's the right answer.

Vinayak said: (Jul 17, 2021)  
All the circles have a line of symmetry except for the third option. And, all the options but the third have an even number of leaves. So, it will be the answer.

Shubhaksh said: (Aug 4, 2021)  
Yeah exactly, 3rd has odd leaves, others have even. So, it is the answer.

Rajat said: (Aug 19, 2021)  
I think option 1 is also correct because it is the only complete figure and the rest are incomplete.

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