Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is .
True
False
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
67 comments Page 5 of 7.

PRADEEP VERMA said:   1 decade ago
MAX.DEFLECTION = Wab^3/3EI(a+b) = Wab^3/3EIL.

SUJAY LONDHE said:   1 decade ago
Given value is Deflection at Point C.
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).

Ravinder kumar said:   1 decade ago
In simply supported beam max.defletion is at center of beam.

Sanchez said:   1 decade ago
By McCauley's method.

Max deflection = wba3/3EI as max deflection occur under loading i.e. - x=a from left support.

Jayanaidu said:   1 decade ago
Above question is satisfying the equation when a=l/2, b=l/2 in the w*a^2*b^2/48EI.

Sumit Dharmarao said:   1 decade ago
Whatever mentioned above is deflection at C & Max. Deflection = ((wa(l^2-a^2)^1.5))/9*3^(1/2)*EIl)).

Prasad said:   1 decade ago
When simply supported beam deflection is wl3/48EI AND IS satisfy above equation if we take a and b equal to L/2.

Prakash said:   1 decade ago
When simply supported beam always maximum deflection occurs at centre of the beam.

Ash said:   1 decade ago
Max Deflection = Wa/9underroot3 EIL * (Lsquare - a square)rest to 3/2.

Chirag sakariya said:   1 decade ago
If we take a and b equal to L/2 then this equation doesn't satisfy the equation of central loaded beam = Wl3/48EI.

So this is wrong Question Or the Answer given here is Wrong.


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