Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is 
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. Discussion:
67 comments Page 1 of 7.
Skd said:
1 decade ago
Its a simple case of concentrated load and can be solved by Macaulay's method easily.
Nandhakumar said:
1 decade ago
In a simply supported beam maximum deflection always occur at the center of the beam.
Chirag sakariya said:
1 decade ago
If we take a and b equal to L/2 then this equation doesn't satisfy the equation of central loaded beam = Wl3/48EI.
So this is wrong Question Or the Answer given here is Wrong.
So this is wrong Question Or the Answer given here is Wrong.
Ash said:
1 decade ago
Max Deflection = Wa/9underroot3 EIL * (Lsquare - a square)rest to 3/2.
Prakash said:
1 decade ago
When simply supported beam always maximum deflection occurs at centre of the beam.
Prasad said:
1 decade ago
When simply supported beam deflection is wl3/48EI AND IS satisfy above equation if we take a and b equal to L/2.
Sumit Dharmarao said:
1 decade ago
Whatever mentioned above is deflection at C & Max. Deflection = ((wa(l^2-a^2)^1.5))/9*3^(1/2)*EIl)).
Jayanaidu said:
1 decade ago
Above question is satisfying the equation when a=l/2, b=l/2 in the w*a^2*b^2/48EI.
Hanu said:
1 decade ago
In simply supported beam max deflection occurs at center of the load applied.
Ravinder kumar said:
1 decade ago
In simply supported beam max.defletion is at center of beam.
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