Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is 
.
. Discussion:
67 comments Page 2 of 7.
SUJAY LONDHE said:
1 decade ago
Given value is Deflection at Point C.
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).
PRADEEP VERMA said:
1 decade ago
MAX.DEFLECTION = Wab^3/3EI(a+b) = Wab^3/3EIL.
Gaurav said:
1 decade ago
Answer should be A.
Max.deflection = WL^3/48EI.
Put a = b = L/2.
Max.deflection = WL^3/48EI.
Put a = b = L/2.
Rajesh said:
1 decade ago
Ans: A.
Maximum deflection at the center = (wl^3)/(192EI) if a = b = l/2.
Maximum deflection at the center = (wl^3)/(192EI) if a = b = l/2.
Pitla prakash said:
1 decade ago
Maximum deflection occurs at center.
Tushar Jha said:
1 decade ago
Answer should be A. Since the deflection at any point on a SSB is given by the same formula. It can be verified for maximum deflection at center for a SSB.
Kokre dnyanoa said:
1 decade ago
Apply McCauley's method. They can easily solve this concept.
Sanchez said:
1 decade ago
By McCauley's method.
Max deflection = wba3/3EI as max deflection occur under loading i.e. - x=a from left support.
Max deflection = wba3/3EI as max deflection occur under loading i.e. - x=a from left support.
Gauri shankar said:
1 decade ago
Max deflection: Y = -2wa^3b^2/3EI (3a+b)^2.
Utkarsh said:
10 years ago
Maximum deflection = -Wa2b2/3EIL (There is use negative sign).
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