Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is 
.
. Discussion:
67 comments Page 4 of 7.
Rajkotha said:
7 years ago
In simply supported beams deflection =Wl^3/48EI.
In simpy supported with UDL deflection =5Wl^4/384EI.
In simpy supported with UDL deflection =5Wl^4/384EI.
Boyka said:
6 years ago
Does it require constant bending moment equation for Macaulay method?
Venu chowdary said:
6 years ago
It's simply supported beam maximum deflection occurs at the midpoint of load applied.
Mohsin said:
6 years ago
Use MOMENT AREA METHOD, you will get max. Deflection as Wa^3b/3LEI.
Hanu said:
1 decade ago
In simply supported beam max deflection occurs at center of the load applied.
Kokre dnyanoa said:
1 decade ago
Apply McCauley's method. They can easily solve this concept.
Tushar Jha said:
1 decade ago
Answer should be A. Since the deflection at any point on a SSB is given by the same formula. It can be verified for maximum deflection at center for a SSB.
Pitla prakash said:
1 decade ago
Maximum deflection occurs at center.
Rajesh said:
1 decade ago
Ans: A.
Maximum deflection at the center = (wl^3)/(192EI) if a = b = l/2.
Maximum deflection at the center = (wl^3)/(192EI) if a = b = l/2.
Gaurav said:
1 decade ago
Answer should be A.
Max.deflection = WL^3/48EI.
Put a = b = L/2.
Max.deflection = WL^3/48EI.
Put a = b = L/2.
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