Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is 
.
. Discussion:
67 comments Page 6 of 7.
Nandhakumar said:
1 decade ago
In a simply supported beam maximum deflection always occur at the center of the beam.
Skd said:
1 decade ago
Its a simple case of concentrated load and can be solved by Macaulay's method easily.
Gauri shankar said:
1 decade ago
Max deflection: Y = -2wa^3b^2/3EI (3a+b)^2.
Utkarsh said:
10 years ago
Maximum deflection = -Wa2b2/3EIL (There is use negative sign).
Rahul kumar said:
10 years ago
They have used 3EIL. Which is wrong? L should not be there.
Sagar k.r said:
10 years ago
The deflection at C is true, since b & a .
Therefore, maximum deflection occurs in CB.
Therefore, maximum deflection occurs in CB.
Anant Kumar said:
9 years ago
Here in question given (Wa2b2/3EIL). So read the question carefully.
If you put a = b = (L/2). Then it satisfies the equation as we know that for simply supported beam max deflection is,
(WL^3/48EI).
So given answer is wrong.
Option A is the correct answer.
If you put a = b = (L/2). Then it satisfies the equation as we know that for simply supported beam max deflection is,
(WL^3/48EI).
So given answer is wrong.
Option A is the correct answer.
PRADEEP said:
9 years ago
Here it is a simply supported beam with eccentric loading (wa2b2/3eil). Which is absolutely correct. Hence by substitution a = L/2, we can get the maximum deflection at mid point.
Gouri said:
9 years ago
I too say that the correct answer will be A.
Abhijit mondal said:
9 years ago
Option A is the right answer.
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