Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 6 (Q.No. 5)
5.
At the neutral axis of a beam, the shear stress is
zero
minimum
maximum
infinity
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
24 comments Page 1 of 3.

Niraj said:   5 years ago
At neutral axis, there is no stress of any kind. Then how maximum?
(2)

Pratik said:   3 years ago
The Answer should be Zero as on the neutral axis radius will be zero so shear stress will also be zero.
(1)

Dheeraj said:   6 years ago
Yes, answer is right, shear stress =SAy'/Ib,

Where, S=shear force, A =area, y'=distance of centroid of area from NA. I=moi, b=width, Here, A and y' are varied wrt y, when you take the values of both in equation and after differenciating it, you will get, y=0, (consider a elementary area at a why distance from NA).

Harsh said:   3 years ago
I agree with you @Amit Choudhary.

JAYDIP PARMAR said:   4 years ago
I think C is the right answer.

Kunal said:   4 years ago
Maximum is the right answer.

Mahesh RP said:   4 years ago
Why max is measured from the top or bottom fibre. Shear stress is max. At the centre and min. At the top and bottom fibre.

Abbas Ali said:   5 years ago
Answer should be None.

Only in pure bending stress or something else alone(Centrod = N.A). It is generally told so it may not always the case.

Correct answer D.None.

Anantha said:   6 years ago
Shear stress is zero in neutral axis and B.M is maximum are called as neutral axis.

Arjun biswas said:   6 years ago
Shear stress = F/2I (d^2/4-y^2) where, F= shear force, I= moment of inertia, d= depth of beam, y= distance from the neutral axis.

So, the maximum shear stress occurs at the neutral axis and is zero at both the top and bottom surface of the beam.


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