Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 6 (Q.No. 5)
5.
At the neutral axis of a beam, the shear stress is
Discussion:
24 comments Page 3 of 3.
Rohit said:
9 years ago
The shear stress varies parabolically in the beam. It is maximum at the center and zero at fibres. The maximum shear force at neutral axis is given by s = 3F/2bd.
RAJU GHOSH said:
9 years ago
I think the answer is A.
Amit choudhary said:
9 years ago
In case of beam, we know;
f = (E/R) * y.
Where f = shear stress, E= youngs modulus, R= radius of curvature and y= distance of layer from the neutral axis.
In this equation E and R are constant for a particular beam and y=0 at neutral axis, therefore, f=0 at the neutral axis.
f = (E/R) * y.
Where f = shear stress, E= youngs modulus, R= radius of curvature and y= distance of layer from the neutral axis.
In this equation E and R are constant for a particular beam and y=0 at neutral axis, therefore, f=0 at the neutral axis.
Kartik said:
10 years ago
In case of beam shear stress is maximum but in case of torsion shear stress at the neutral axis is zero.
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