Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 2 (Q.No. 16)
16.
The extremeties of any diameter on Mohr's circle represent
principal stresses
normal stresses on planes at 45°
shear stresses on planes at 45°
normal and shear stresses on a plane
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 2 of 3.

Ankit said:   8 years ago
Yes, I think option D is correct because every point on Mohr circle perimeter or extremities of any diameter on Mohr's circle represent normal and shear stresses in a different direction at a point.

R durgaprasad said:   8 years ago
I think option D is correct.

Sandiarta said:   8 years ago
Why is it B? I think it should be D.

Vijay kumar said:   8 years ago
It gives both normal and shear.

Amar said:   8 years ago
Which one is the correct answer? Explain.

Ankit said:   8 years ago
Option D is correct.

M. Rizwan said:   8 years ago
The option B is correct because at 45 degrees Mohr's circle will take it as 90 degrees. So at this angle normal stress will be equal to the maximum shear stress which is radius on any point of mohr's circle.

Akshay.kelzarkar said:   8 years ago
Rizwan you got this actually at any point on the mohr's circle represents the maximum shear stress and maximum stress is at the plane 45° to the normal stress plane.
Right answer is 'B'.

Shivom said:   8 years ago
Option D is correct, I think.

Vohra akil said:   8 years ago
This question is for only uniaxial stress condition?

If biaxial stress condition then normal stress on at 45° inclined planes is not equal to maximum shear stress( radius of Mohr circle).
(1)


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