Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 2 (Q.No. 16)
16.
The extremeties of any diameter on Mohr's circle represent
principal stresses
normal stresses on planes at 45°
shear stresses on planes at 45°
normal and shear stresses on a plane
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 1 of 3.

Shail said:   6 years ago
A is thw right ans.. as extremities of dia. are points of principal stresses.. since extremities means the end points of the dia. Which shows the principal stresses.. normal stress is at the point in sumwhere b/w the dia.. bt not the extremities

M. Rizwan said:   8 years ago
The option B is correct because at 45 degrees Mohr's circle will take it as 90 degrees. So at this angle normal stress will be equal to the maximum shear stress which is radius on any point of mohr's circle.

Ankit said:   8 years ago
Yes, I think option D is correct because every point on Mohr circle perimeter or extremities of any diameter on Mohr's circle represent normal and shear stresses in a different direction at a point.

Spitfire said:   6 years ago
Extremities of any diameter tell us the normal stresses and shear stresses on planes at 90 degrees to each other since the diameter subtends an angle of 180 degrees = 2 * θ in Mohr's circle.
(1)

Vohra akil said:   8 years ago
This question is for only uniaxial stress condition?

If biaxial stress condition then normal stress on at 45° inclined planes is not equal to maximum shear stress( radius of Mohr circle).
(1)

Akshay.kelzarkar said:   8 years ago
Rizwan you got this actually at any point on the mohr's circle represents the maximum shear stress and maximum stress is at the plane 45° to the normal stress plane.
Right answer is 'B'.

Sachin swapnil said:   7 years ago
Option A is the correct answer.

Principal stress is the correct Answer.

Extremities means diameter ends on X-axis represents max and min principal stresses so answer is definately A.
(1)

Usama Ata said:   4 years ago
Right answer is B because we find sigma X and sigma why from Mohr's circle (and diameter=sigma X+ sigma y).

And shear stress is equal to radius, Not diameter.

Expert's Advice said:   1 decade ago
Option [B] is a special case when both shear and direct stress are there. But as per question option [D] is correct. @Abhishek has given the explanation.

Abhishek said:   1 decade ago
D Option is correct as the x- coordinate in Mohr's circle contains the normal stress but the Y Axis also contain the shear stress values.


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