Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 16)
16.
The extremeties of any diameter on Mohr's circle represent
Discussion:
30 comments Page 1 of 3.
Vinay said:
5 years ago
The Correct answer should be D.
(3)
Jayesh said:
7 years ago
The correct Answer is D.
(2)
Nil pandya said:
5 years ago
The Correct answer should be D.
(1)
Spitfire said:
6 years ago
Extremities of any diameter tell us the normal stresses and shear stresses on planes at 90 degrees to each other since the diameter subtends an angle of 180 degrees = 2 * θ in Mohr's circle.
(1)
Sachin swapnil said:
7 years ago
Option A is the correct answer.
Principal stress is the correct Answer.
Extremities means diameter ends on X-axis represents max and min principal stresses so answer is definately A.
Principal stress is the correct Answer.
Extremities means diameter ends on X-axis represents max and min principal stresses so answer is definately A.
(1)
DHARMJeet said:
7 years ago
According to me, D is the correct answer.
(1)
Vohra akil said:
8 years ago
This question is for only uniaxial stress condition?
If biaxial stress condition then normal stress on at 45° inclined planes is not equal to maximum shear stress( radius of Mohr circle).
If biaxial stress condition then normal stress on at 45° inclined planes is not equal to maximum shear stress( radius of Mohr circle).
(1)
Ankit said:
8 years ago
Option D is correct.
Usama Ata said:
4 years ago
Right answer is B because we find sigma X and sigma why from Mohr's circle (and diameter=sigma X+ sigma y).
And shear stress is equal to radius, Not diameter.
And shear stress is equal to radius, Not diameter.
Gopi said:
4 years ago
The right Answer should be principal stresses.
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