Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Discussion:
57 comments Page 3 of 6.
Sumit said:
1 decade ago
Principal Stress: Maximum and minimum normal stress possible for a specific point on a structural element.
Bangaram said:
7 years ago
1200+6000/2+1/2 ( (1200-600) + 4 (400) ) =1400mpa.
So it is by using formula of maximum normal stress.
So it is by using formula of maximum normal stress.
(7)
Atosh said:
9 years ago
The maximum and minimum normal stresses (σ1 and σ2) are known as the principal stresses.
Khagesh said:
1 decade ago
Principal stress are maximum and minimum normal stress which may be developed on a loaded body.
Rakesh patra said:
8 years ago
Principle stress are maximum or minimum normal stress which may be developed on a loaded body.
Yajat Sharma said:
10 years ago
Maximum. normal stress = T.S - S.S.
= T.S1 + T.S2 - S.S.
= 1200 + 600 - 400 .
= 1400 answer.
= T.S1 + T.S2 - S.S.
= 1200 + 600 - 400 .
= 1400 answer.
Rahul prajapati said:
1 decade ago
@Amol and @Arshad this formula is used for max. Principal stress not for max normal stress.
Avneesh said:
9 years ago
You can also use this formula,
Stress = [(x + y)/2] + 0.5 * (x - y)^2 + 4(shear stress)^2.
Stress = [(x + y)/2] + 0.5 * (x - y)^2 + 4(shear stress)^2.
Rohit said:
1 decade ago
@Amol is this formula applicable for finding Max. Normal stress in all types of questions?
Amol Kamale said:
1 decade ago
Yes, this formula applicable for finding Max. Normal stress in all types of questions.
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